What is 30.7 rounded to the nearest ones place

Your sister starts a new business selling iced tea. She borrowed money from you for the initial supplies, which cost a total of

Ivenika [448]

Answer:

Question 1 - she will make $10.50 and still owe you $5.25 because 0.35 x 30 = 10.25

question 2 - for this im not sure because the 2nd, 3rd and 4th wont work so it should be the first but I’m not sure what that equation is saying

question 3 - 29 glasses need to be sold

6 0

3 years ago

Dawn's credit card has an APR of 15%, calculated on the previous monthly

hodyreva [135]

125.13

Step-by-step explanation:

8 0

3 years ago

How to graph y= -X-3

sukhopar [10]

Step-by-step explanation:

It's the equation of a line.

We need only two points to the plotting a graph of a line.

y = -x - 3

for x = -3

y = -(-3) - 3 = 3 - 3 = 0 → (-3, 0)

for x = 0

y = -0 - 3 = 0 - 3 = -3 → (0, -3)

6 0

4 years ago

PLEASE I NEED HELP

Lady_Fox [76]

$\bf \begin{cases} x-2y=-7\\ x-y=9\implies \boxed{x}=9+y \end{cases} \\\\\\ \stackrel{\textit{substituting \underline{x} in the first equation}}{\boxed{9+y}-2y=-7}\implies -y=-16 \\\\\\ y=\cfrac{-16}{-1}\implies y=16\\\\ -------------------------------\\\\ \stackrel{\textit{and substituting \underline{y} in the first equation}}{x-2(16)=-7}\implies x-32=-7\implies x=25 \\\\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~(\stackrel{x}{25}~~,~~\stackrel{y}{16})$

6 0

3 years ago

Over the past several years, the proportion of one-person households has been increasing. The Census Bureau would like to test t

bixtya [17]

Answer:

For this case we can find the critical value with the significance level $\alpha=0.05$ and if we find in the right tail of the z distribution we got:

$z_{\alpha}= 1.64$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.344 -0.27}{\sqrt{\frac{0.27(1-0.27)}{125}}}=1.86$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of households with one person is significantly higher than 0.27

Step-by-step explanation:

We have the following dataset given:

$X= 43$ represent the households consisted of one person

$n= 125$ represent the sample size

$\hat p= \frac{43}{125}= 0.344$ estimated proportion of households consisted of one person

We want to test the following hypothesis:

Null hypothesis: $p \leq 0.27$

Alternative hypothesis: $p>0.27$

And for this case we can find the critical value with the significance level $\alpha=0.05$ and if we find in the right tail of the z distribution we got:

$z_{\alpha}= 1.64$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.344 -0.27}{\sqrt{\frac{0.27(1-0.27)}{125}}}=1.86$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of households with one person is significantly higher than 0.27

5 0

3 years ago