I ready scientific notation help

Mathematics

1 answer:

Airida [17]3 years ago

4 0

The required value is $2\times10^9$

Step-by-step explanation:

Weight of ants = $4\times10^{-3}$

Weight of elephant= $8\times10^6$

We need to find, the total weight of about how many ants equals to the weight of an oversized elephant.

The equation given is:

$4\times10^{-3} \times a = 8\times10^6$

We need to find a:

Solving:

$4\times10^{-3} \times a = 8\times10^6\\a=\frac{8\times10^6}{4\times10^{-3}}\\if \,\,10^a/10^-b \,\,then\,\, 10^{a+b}\\a=2\times10^{6+3} \\a=2\times10^9$

So, the required value is $2\times10^9$

Keywords: Scientific Notation

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Evaluate the expression. 33 + 6( 2 + 36 )

Alinara [238K]

Answer: 261

Step-by-step explanation:

You use PEMDAS to solve this problem

you first do the Parenthesis (p)

33+6(2+36)

33+6 (38)

We then multiply first (M)

33 + 6(38) - we know that 8 times 6 is 48 ; 6 times 3 is 18 +4 because we brought down the 4 from 48 to 3. which will be equal to 228

33 + 228

261

8 0

3 years ago

A card is drawn randomly from a standard deck of cards. you win $10 if the card is a spade or an ace. what is the probability th

klio [65]

The probability of winning is 4/13.

These two events are not mutually exclusive; this means they can happen at the same time. For two events that are not mutually exclusive,

P(A or B) = P(A) + P(B) - P(A and B)

This gives us
P(spades or Ace) = P(spades) + P(Ace) - P(spades and Ace)

There are 13 spades out of 52 cards.
There are 4 aces out of 52 cards.
There is 1 card that is a spade and an ace out of 52 cards.

13/52 + 4/52 - 1/52 = 16/52 = 4/13

3 0

3 years ago

5x-2y=-6 3x-4y = -26

snow_tiger [21]

For this case we must solve the following system of equations:

$5x-2y = -6\\3x-4y = -26$