Write out all the pairs of numbers which can be multiplied to produce c.
Add each pair of numbers to find a pair that produce b when added. ...
If b > 0, then the factored form of the trinomial is (x + d )(x + e). ...
Check: The binomials, when multiplied, should equal the original trinomial.
Blocks would he need on the 12th step of the pattern is 34.
The correct option is A
<h3>
</h3><h3>What is series?</h3>
A series is the cumulative sum of a given sequence of terms.
Given:
We can write the series as follows:
1,4,7,10,13,.......
First term =1
common difference= 4-1=3
Using Arithmetic series
= a+11d
= 1 +11*3
= 1+33
= 34.
Hence, 34 blocks need on 12th step.
Learn more about arithmetic series here:
brainly.com/question/2171130
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Answer:
156 different pairs will be there.
Step-by-step explanation:
As the order is essential as we need different pairs therefore permutations will be used.
A permutation is any ordered subset of the objects r selected with regard to their order, from the set of n distinct objects. It is given by nPr where n> r
Total number is 13 and required number is 2
n= 13 and r= 2
13 P2= 156 possible combinations.
A combination is any subset of the objects r selected without regard to their order, from the set of n distinct objects. It is given by nCr where n> r
Answer:
s mae é uma vuaad iaauela q2 prostittu0a dsgreaaç, bv aid a respostalalogo q
Step-by-step explanation:
Answer:
Step-by-step explanation:The problem is very hard to read. When using exponents, please add the "^" in front. For example, is 132 actually 132, or is it 13^2? The right triangle is not shown, so we really don't know which is the hypotenuse. Also be carefull with spacing. Making some assumptions, here is how the answer might look:
Both have the correct formula: a^2 + b^2 = c^2, assuming c is the hypotenuse.
If c is the hypotenuse, then the expression should be:
7^2 + b^2 = 13^2, or
49 + b^2 = 169
I like Sheridan's answer. So let's continue:
49 + b^2 = 169
b^2 = 169-49
b^2 = 120
b = 10.954 . . .
Yep, I'm on Sheridan's side. [That is, unless 72 is 72 and not 7^2, etc.]
