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ikadub [295]
3 years ago
8

the cost of 6 pounds of beef is $39 what is the constant of proportionality that relates the cost in dollars y to the number of

pounds of beef x?
Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

5/1/2 hope i helped have a good day
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What is -16, -15.7, -15 1/2, -16 1/4 in greatest to least
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-161/4<-16<-15.7<-151/2
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A computer has a sales price of $150, and is advertised for 25% off of the original price.
Firlakuza [10]

Answer:

Original price:$150

Markdown percentage:25%

Sale price:$112.50

Discount savings:$37.50

Step-by-step explanation:

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Determine the amplitude of the following graph.​
kodGreya [7K]

Answer:

amplitude = 3

Step-by-step explanation:

the amplitude is the vertical distance from center of the wave to the crest or the trough

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3 years ago
(c + b + a) + (-2a - 3b + c)
inna [77]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>2c - 2b - a</em>

▹ Step-by-Step Explanation

(c + b + a) + (-2a - 3b + c)

<u>Remove the parentheses</u>

c + b + a + (-2a - 3b + c)

<u>Collect like terms</u>

2c + b + a - 2a - 3b

<u>Final Answer</u>

2c - 2b - a

Hope this helps!

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1. Construct a table of values of the following functions using the interval of 5
Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

g(x) = \frac{x^3 + 3x - 5}{x^2}

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When x = -5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}

g(-5) = \frac{-125 -15 - 5}{25}

g(-5) = \frac{-145}{25}

g(-5) = -5.8

When x = -4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}

g(-4) = \frac{-64 -12 - 5}{16}

g(-4) = \frac{-81}{16}

g(-4) = -5.0625

When x = -3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}

g(-3) = \frac{-27 -9 - 5}{9}

g(-3) = \frac{-41}{9}

g(-3) = -4.56

When x = -2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}

g(-2) = \frac{-8 -6 - 5}{4}

g(-2) = \frac{-19}{4}

g(-2) = -4.75

When x = -1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}

g(-1) = \frac{-1 + 3 - 5}{1}

g(-1) = \frac{-3}{1}

g(-1) = -3

When x = 0

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(0) = \frac{0^3 + 3(0) - 5}{0^2}

g(0) = \frac{0 + 0 - 5}{0}

g(0) = \frac{- 5}{0}

<em>g(0) = undefined</em>

When x = 1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(1) = \frac{1^3 + 3(1) - 5}{1^2}

g(1) = \frac{1 + 3 - 5}{1}

g(1) = \frac{-1}{1}

g(1) = 1

When x = 2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(2) = \frac{2^3 + 3(2) - 5}{2^2}

g(2) = \frac{8 + 6 - 5}{4}

g(2) = \frac{9}{4}

g(2) = 2.25

When x = 3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(3) = \frac{3^3 + 3(3) - 5}{3^2}

g(3) = \frac{27 + 9 - 5}{9}

g(3) = \frac{31}{9}

g(3) = 3.44

When x = 4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(4) = \frac{4^3 + 3(4) - 5}{4^2}

g(4) = \frac{64 + 12 - 5}{16}

g(4) = \frac{71}{16}

g(4) = 4.4375

When x = 5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(5) = \frac{5^3 + 3(5) - 5}{5^2}

g(5) = \frac{125 + 15 - 5}{25}

g(5) = \frac{135}{25}

g(5) = 5.4

<em>Hence, the complete table is:</em>

x  ---- g(x)

-5 --- -5.8

-4 --- -5.0625    

-3 --- -4.56

-2 --- -4.75  

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0
3 years ago
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