Answer:
opiton b
Step-by-step explanation:
To find out which equation satisfies h(x) we need to check with each option
We plug in x value
A) h(–1.25) = –0.5
Plug in -1.25 for x in h(x) = 16^x
That is not true
B) h(–0.5) = 0.25
Plug in -0.5 for x
That is true.
C) h(0.75) = 12
Plug in 0.75 for x
That is not true.
D) h(1.25) = 20
Plug in 1.25 for x
That is not true
<em>Lets say that √(3+i) is the magnitude of your vector. In polar form, i represents the x component and j represents the y component of the vector. Therefore, the polar form is icosθ√(3+i) + jsinθ√(3+i)</em>
draw a diagram :
<em>z = r(cos θ + i sin θ), where z = complex number, r = modulus, θ = angle of rotation For the given:r = 2θ = π/6 √3 + i = 2(cos π/6 + i sin π/6)</em>
<em>hope</em><em> </em><em>thz</em><em> </em><em>hlpz</em><em> </em><em>✿</em>
3x+y=4 (y=-3x+4)
Plug it in for y x+2(-3x+4)=-2
x=2
Plug in for x 2+2y=-2
y=-2
Solution: (2,-2)
Answer:
3y + 5x = 0
Step-by-step explanation:
The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))
= 5 / -3 = -5/3
Using the point-slope form , the line that passes through the origin and parallel to this line is
y - 0 = -5/3(x - 0)
y = -5/3 x
Multiply through by 3:-
3y = -5x
5x + 3y = 0
