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wel
3 years ago
15

PLEEAAASSSEEEEE HEEELLLLLPPPPPP

Mathematics
2 answers:
likoan [24]3 years ago
8 0

The answer should be simple random sampling... Not 100% sure though..

Nikolay [14]3 years ago
4 0

simple random sampling

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Use P E M D A S to solve this number problem.
eimsori [14]
Yes your answer is correct
5 0
3 years ago
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-5+7q+ -5q+ -9q please help
vekshin1

For this case we must simplify the following expression

-5 + 7q + (- 5q) + (- 9q)

We know that, by definition:

+ * - = -

So, rewriting the expression we have:

-5 + 7q-5q-9q =

We add similar terms taking into account that:

  • Equal signs are added and the same sign is placed.
  • Different signs are subtracted and the major's sign is placed:

-5 + 2q-9q =\\-5-7q

Answer:

-5-7q

5 0
4 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
The diameter of a sphere is 6 cm. What is the volume of the sphere?
irinina [24]

Answer:

36pi

Step-by-step explanation:

the volume of a sphere is equal to 4/3 x pi x r^3

the radius is half of the diameter

3^3=27

27x4/3=36

36pi

6 0
3 years ago
Does anyone whatsoever have any tips for coordinate plane- like I need alot please. anything you know that helps u.
Anon25 [30]

Most of the time for coordinate planes, they are asking you to plot the point correctly, and to state which quadrant the point falls into.

The Quadrant points start at (+ , +) for Quadrant I, and moves clockwise. See attached picture.

Quadrant I: (+ , +)

Quadrant II: (+ , -)

Quadrant III: (- , -)

Quadrant IV: (- , +)

Remember, the point is split into two parts, in which the first one is x (which signifies the placement for the horizontal line), while the other is y (which signifies the placement for the vertical line).

~

7 0
3 years ago
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