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Mathematics

2 answers:

likoan [24]2 years ago

8 0

The answer should be simple random sampling... Not 100% sure though..

Nikolay [14]2 years ago

4 0

simple random sampling

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Write the equation of a line that is perpendicular to x=3x=3x, equals, 3 and that passes through the point (0,-4)(0,−4)left pare

leva [86]

Answer: $x+3y=12$

Step-by-step explanation:

Slope of two lines that are perpendicular to each other is 1.

If one line is $y=3x$ , then its slope = 3 [by comparing to the linear equation y= mx+c, here m=3]

Let n be the slope of the required line, then

$n\times3=-1\\\\\rightarrow\ n=\dfrac{-1}{3}$

Equation of line with slope n and passers through (a,b) is

$(y-b)=n(x-a)$

Equation of line with slope n= $\dfrac{-1}{3}$ and passes through point ( 0,-4) :

$(y-(-4))=\dfrac{-1}{3}(x-0)\\\\\Rightarrow\ y+4=\dfrac{-1}{3}x\\\\\Rightarrow\ -3(y+4)=x\\\\\Rightarrow-3y-12=x\\\\\Rightarrow x+3y=12$

Hence, Required equation : $x+3y=12$

8 0

3 years ago

Which is the equation of a line with a slope of -1 and a y-intercept of -6?

nikklg [1K]

Answer:

y= -1x - 6

I really hope this helps you!

3 0

3 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$