Find the area of the smaller sector. Round to the nearest tenth.
1 answer:
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Answer:
∴V=(14-2x)(10-2x)x
where V is the volume of the box in cubic units.
Step-by-step explanation:
Given that,
A rectangle has a length of 14 units and width of 10 units.
4 squares with dimensions x by x units are cut out from the each corner of the rectangle.
The length of the box is= (14-2x) units
The width of the box is =(10-2x) units
The height of the box is = x unit.
The volume of the box is = Length × width×height
=(14-2x)(10-2x)x cubic units.
∴V=(14-2x)(10-2x)x
where V is the volume of the box in cubic units.
