Answer:
there is no solution for x
Step-by-step explanation:
BTW you can use math.way
Well, Mark has
1 1/3 of yellow paint
1 1/4 of green paint and
7/8 of blue paint
now, bear in mind, the yellow is a bucket and 1/3 more, the green one is one bucket and 1/4 more and the blue is 7/8 which is almost 8/8, so is almost a bucketfull.
Then he's going to use 3/4 of each, so, we'd have to subtract 3/4 from each, and there'll be some left still in the paint bucket.
How many will he have left altogether? well, we simply add the leftovers.
Value of the coin times number of coins summed up equal total value
so since we have "$2.10 in all"...
0.05n + 0.25q = 2.10
and we are told that there are "four times as many quarters as nickels"
this translates to
q = 4n
0.05n + 0.25q = 2.10
and
q = 4n
are your two equations that could be used to solve this problem
if you would like to know how many nickels and how many quarters there are, plug in q = 4n into the first equation and get
0.05n + 0.25(4n) = 2.10
multiply
0.05n + 1n = 2.10
add like terms
1.05n = 2.10
divide both sides by 1.05
n = 2.10/1.05 = 2
then plug that back into
q = 4n
so
q = 4(2) = 8
therefore you have
2 nickels
and
8 quarters
Answer:
D) Impossible
Step-by-step explanation:
As in a standard die , the values are from 1 to 6.
So, If the die is rolled then its impossible to land on 0.