Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
32 divided by 127 and the second one, i dont know
It is (5x + 6) (x + 2)
The way of deriving this is through cross multiplication
Answer:
the answer is 7
Step-by-step explanation:
Answer:
d. 9
Step-by-step explanation:
it can't be the rest... ion even know how to explain it.