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ss7ja [257]
3 years ago
5

John's monthly paycheck consists of $4,000 plus a 9% commission on all of his sales. During one month, John earned $11,650. What

were his sales during that month?
Mathematics
1 answer:
MrRa [10]3 years ago
7 0

The problem statement tells us ...

... paycheck = 4000 + 0.09×sales

and that the paycheck amount is 11650. Substituting that into the above equation and solving for sales, we have ...

... 11650 = 4000 + 0.09×sales

... 7650 = 0.09×sales . . . . . . . . . . subract 4000

... 7650/0.09 = sales = 85000 . . . divide by 0.09

John's sales during that month were $85,000.

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a box with a square base and open top must have a volume of 70304 c m 3 cm3 . we wish to find the dimensions of the box that min
Dmitriy789 [7]

The box should have base 52 cm by 52 cm and height 26 cm.

What is volume?

A three-dimensional space's occupied volume is measured. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.

The Volume of a box with a square base x by x cm and height h cm is

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Since the surface area directly affects the amount of material used, we can reduce the amount of material by reducing the surface area.

The surface area of the box described is  A = x^2 + 4xh

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So, the area becomes,

A = x^2+4x(\frac{70304}{x^2})\\ A = x^2 + \frac{281216}{x}

We want to minimize A, so

A' = 2x - \frac{281216}{x^2} =0\\\frac{2x^3-281216}{x^2}=0\\ {2x^3-281216} = 0\\x^3 - 140608=0\\x^3 = 140608\\x = 52

The second derivative test verifies that A has a minimum at this critical number:

A'' = 2+\frac{562432}{x^3}  which is positive at x = 52.

Now,

h = \frac{70304}{x^2}= \frac{70304}{(52)^2}=26

Hence, The box should have base 52 cm by 52 cm and height 26 cm.

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