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GenaCL600 [577]
3 years ago
12

In the expression (x2 + 3), the base is _____.

Mathematics
2 answers:
matrenka [14]3 years ago
6 0

In the expression (x2 + 3), the base is x.

Yuri [45]3 years ago
5 0

Answer:

x is the base in (x^2 + 3)

Step-by-step explanation:

The base is x because it is being raised to a square or to the 2nd power  in (x^2 + 3). The base of an expression or exponent is always the number that is being raised to a power.  

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Solve for x. −68<8x−4<−36
Lelu [443]

x equals negative 8 and negative 4


3 0
4 years ago
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Anna saved $20 in a jar each month for 2/1/2 years. She spent 75% of her savings on a computer. How much money did Anna have lef
strojnjashka [21]
2 and 1/2 years = 30 months

20 \times 30 = 600
100\% - 75\% = 25\%
600 \times 25\% = 150
The answer is A. $150

Hope this helps.
6 0
3 years ago
A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p
gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0
3 years ago
Viyan age is 2 / 5 of the age of her eldest brother. If his brother's age is 35 years, then how old is viyan?
sashaice [31]
I think it’s 14 I hope
6 0
3 years ago
A veterinary clinic saw 45 pets on Monday. The shaded squares in the grid below represent the 60% of pets
Black_prince [1.1K]
Answer: 27 dogs were seen at the clinic on monday.

27/45 = 0.6

0.6 = 60%
3 0
2 years ago
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