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Lesechka [4]
3 years ago
9

Which of the following would happen if the normal force and gravitational force acting on an object were unequal?

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0

Well, the normal force and the force of gravity are equal, however, they travel in opposite directions. Mass never changes and temperature has to do with the ambient environment and the object itself. That eliminates 3 and 4. The force of gravity pulls downwards as we see it, so that eliminates option 1. Your answer is option 2.

Answer: The object would move up or down(Option 2)

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What is the value of g in 1/3s + 14 = 26
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Answer:

s = 36

Step-by-step explanation:

So what you do is isolate the s.

1. Subtract 14 from both sides of equation. You should have:

1/3s = 12

2. To isolate the s, you multiply by 3 on both sides to get rid of the fraction on the left side. You should have:

s = 36

To verify, plug into original equation:

1/3*(36) + 14 = 26

1/3 * 36 = 36/3 = 12

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Step-by-step explanation:

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2 years ago
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Please help, I will mark!!
Alik [6]

Answer:

d=28.28

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

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To find the value of the lenght of the diagonal d across the square, we have:

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d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284

Round the answer to 2 decimal places

d=28.28

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3 years ago
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