d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
M= change in y /change in x
(−10, 4), (2, −5)
M= -5-4/2-(-10)
M= -9/12
M- 3/4
Slope is - 3/4
Answer:
1500 millimeters
Step-by-step explanation:
the answer to your question is -12
Answer:
x = 17 and y = 10
Step-by-step explanation:
ABCD is a parallelogram
So AB = CD and AD = BC
so
3x - 9 = 42
3x = 51
x = 17
and
4y - 3 = 37
4y = 40
y = 10
Answer
x = 17 and y = 10
