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3 years ago

Can someone help me on these ???

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

Multiply 81.5p and divide 7.5% you get the answer

Serjik [45]3 years ago

8 0

It can take 1200 liters....and it already has 450 liters.....so it needs (1200 - 450) = 750 liters to fill it up to full capacity.

and the price is 81.5 pounds per liter......for 750 liters...
81.5 * 750 = $ 61125 pounds

and he gets a 7.5% discount...
so his discount would be : 0.075 * 61125 = 4584.375 rounds to
$ 4584.38 pounds <== ur answer

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1/8(-8c +16) - 1/3(6+3c)

Bess [88]

Answer:

-2c

Step-by-step explanation:

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2 years ago

How many ways can 4 people sit in a table of 6 seats? A.120 B.24 C.360 D.15

Mice21 [21]

I believe the is c 360

7 0

3 years ago

Read 2 more answers

Solve for h h - 3h - 8 = 14 H=?

sweet [91]

The initial step that must be taken before solving almost any problem is to understand what the problem is asking for us to do and what is provided to us to complete that goal. Looking at the problem statement, we can see that we are being requested to solve for h and we are provided an expression to do so. Let's begin solving the expression by combining like terms.

Combine like terms

$h - 3h - 8 = 14$

$(h - 3h) - 8 = 14$

$(- 2h) - 8 = 14$

Just a quick explanation on what combine like terms means, it basically just means to combine the coefficients of the numbers associated with the same variables. Like in this example we can combine h and -3h because they have have the variable h associated with them.

Add 8 to both sides

$(- 2h) - 8 = 14$

$(- 2h) - 8+ 8 = 14 + 8$

$- 2h= 22$

Divide both sides by -2

$- 2h= 22$

$\frac{- 2h}{-2}= \frac{22}{-2}$

$h= \frac{22}{-2}$

Simplify the expression

$h= - \frac{22/2}{2/2}$

$h= - \frac{11}{1}$

$h= - 11$

Therefore, after completing the steps above we were able to determine that the value of h is equal to -11.

8 0

2 years ago

Read 2 more answers

Help!!!!!!!!!!!!!!!!!!1

Veseljchak [2.6K]

What do you need help with

8 0

3 years ago

(a) If G is a finite group of even order, show that there must be an element a = e, such that a−1 = a (b) Give an example to sho

Dahasolnce [82]

Answer:

See proof below

Step-by-step explanation:

First, notice that if a≠e and a^-1=a, then a²=e (this is an equivalent way of formulating the problem).

a) Since G has even order, |G|=2n for some positive number n. Let e be the identity element of G. Then A=G\{e} is a set with 2n-1 elements.

Now reason inductively with A by "pairing elements with its inverses":

List A as A={a1,a2,a3,...,a_(2n-1)}. If a1²=e, then we have proved the theorem.

If not, then a1^(-1)≠a1, hence a1^(-1)=aj for some j>1 (it is impossible that a^(-1)=e, since e is the only element in G such that e^(-1)=e). Reorder the elements of A in such a way that a2=a^(-1), therefore a2^(-1)=a1.

Now consider the set A\{a1,a2}={a3,a4,...,a_(2n-1)}. If a3²=e, then we have proved the theorem.

If not, then a3^(-1)≠a1, hence we can reorder this set to get a3^(-1)=a4 (it is impossible that a^(-1)∈{e,a1,a2} because inverses are unique and e^(-1)=e, a1^(-1)=a2, a2^(-1)=a1 and a3∉{e,a1,a2}.

Again, consider A\{a1,a2,a3,a4}={a5,a6,...,a_(2n-1)} and repeat this reasoning. In the k-th step, either we proved the theorem, or obtained that a_(2k-1)^(-1)=a_(2k)

After n-1 steps, if the theorem has not been proven, we end up with the set A\{a1,a2,a3,a4,...,a_(2n-3), a_(2n-2)}={a_(2n-1)}. By process of elimination, we must have that a_(2n-1)^(-1)=a_(2n-1), since this last element was not chosen from any of the previous inverses. Additionally, a_(2n1)≠e by construction. Hence, in any case, the statement holds true.

b) Consider the group (Z3,+), the integers modulo 3 with addition modulo 3. (Z3={0,1,2}). Z3 has odd order, namely |Z3|=3.

Here, e=0. Note that 1²=1+1=2≠e, and 2²=2+2=4mod3=1≠e. Therefore the conclusion of part a) does not hold

7 0

3 years ago