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2 years ago

15

During February Kevin water his IVy every third day and water his Cactus every fifth day well Kevin water both plants together a

gain in February explain

1 answer:

Ivanshal [37]2 years ago

8 0

Kevin will water both of his plants on the 15th.

The lowest common multiple of 3 and 5 is 15. Therefore, he will water both then.

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Please help! Will give Brainliest!

kkurt [141]

Answer:

g(x) = 2|x|
g(x) = -2|x|
g(x) = -2|x| -3
g(x) = -2|x-1| -3

Step-by-step explanation:

1) Vertical stretch is accomplished by multiplying the function value by the stretch factor. When |x| is stretched by a factor of 2, the stretched function is ...

g(x) = 2|x|

__

2) Reflection over the x-axis means each y-value is replaced by its opposite. This is accomplished by multiplying the function value by -1.

g(x) = -2|x|

__

3) As you know from when you plot a point on a graph, shifting it down 3 units subtracts 3 from the y-value.

g(x) = -2|x| -3

__

4) A right-shift by k units means the argument of the function is replaced by x-k. We want a right shift of 1 unit, so ...

g(x) = -2|x -1| -3

7 0

3 years ago

) Every two out of three kids sang at the talent show. What percent of the kids did not sing at the talent show? (round)

SCORPION-xisa [38]

The answer is 33 percent

hope this helps!

4 0

2 years ago

Read 2 more answers

om is the deli manager at a grocery store. He needs to schedule employees to staff the deli department at least 260 person-hours

qwelly [4]

20 + 40x = 260
40x = 260 - 20
40x = 240
x = 240/40
x = 6 fulltime employees needed
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8 0

3 years ago

The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance ca

Nikolay [14]

Based on the given question above, the correct answer would be the fourth option. The <span>circumstance that the cross section can be a non-rectangular parallelogram is that, </span><span>when the plane makes an acute angle to the base and intersects three vertical faces. Hope this answers the question. </span>

7 0

3 years ago

Read 2 more answers

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

<em>l</em> denotes length
<em>b</em> denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0

3 years ago