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Ostrovityanka [42]
3 years ago
7

Which shows the lengths from greatest to least?

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
A because the length is greater
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Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.
aleksley [76]

Given:

The expression is:

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

To find:

The value of the given expression when x=64 and y=27.

Solution:

We have,

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

Putting x=64 and y=27, we get

=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}

It can be written as

=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}

=1+4-2(8)           [\because a^0=1,a\neq 0]

=5-16

=-11

Therefore, the value of the given expression -11 when x=64 and y=27.

4 0
3 years ago
Pls help me quickly
antoniya [11.8K]
What do I solve for?
4 0
3 years ago
Read 2 more answers
Find the missing length indicated. <br> Your answer
Naddika [18.5K]

Answer:

x = 12

Step-by-step explanation:

For the middle size triangle

short leg = x

long leg = (25 - 9) = 16

ratio = x/16

For the small triangle

short leg = 9

long leg = x

ratio = 9/x

Similar triangles are proportional so

Set the ratios equal

x/16 = 9/x

Cross multiply

x² = 144

Take the square root of both sides

x = 12

6 0
3 years ago
Find the volume.<br><br><br> 986 m3<br><br><br> 3,360 m3<br><br><br> 408 m3<br><br><br> 1,680 m3
Jobisdone [24]

Answer:

The volume is 1,680\ m^3

Step-by-step explanation:

we know that

The volume of a triangular prism is

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

B=\frac{1}{2}(28)(12)=168\ m^2

L=10\ m ----> perpendicular distance between the two triangular bases

substitute

V=(168)(10)=1,680\ m^3

4 0
3 years ago
Secants BE and CF intersect at point D inside A. What is the measure of CDE?
Aleks04 [339]
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90

<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120

answer
<CDE = 120°
6 0
3 years ago
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