<span>If Hunter raises beetles in a square of compost with a size of 6 ft by 6 ft and having 500 beetles, and then you are to find the number of beetles with a side length that is four times longer, then you can solve this by ratio and proportion.
A = s</span>²
A = 6²
A = 36 ft²
if s = 4*the original length, then the new area is
A = 24²
A = 576 ft²
500 beetles/36 ft² = x number of beetles/576 ft²
x = 8,000 beetles
Answer:
The pencil marks on your page show you exactly how to do that.
Step-by-step explanation:
Take advantage of two rules of exponents:
![\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5C%5C%5C%5Cx%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7Bn%7D%7D)
![(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}](https://tex.z-dn.net/?f=%28d%29%5Cquad%20x%5E%7B%5Cfrac%7B-1%7D%7B5%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7Bx%7D%7D%5C%5C%5C%5C%28h%29%5Cquad%20x%5E%7B%5Cfrac%7B-2%7D%7B11%7D%7D%3D%5Cdfrac%7B1%7D%7Bx%5E%7B%5Cfrac%7B2%7D%7B11%7D%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%5B11%5D%7Bx%5E%7B2%7D%7D%7D)
The answer is Would be 2 hehehehe hshshs x=2
The percentage of students voted for colour crimson
=
hope it helps!
Answer:
<h2><u><em>
168</em></u></h2>
Step-by-step explanation:
350 : (5 + 8 + 12) =
350 : 25 = 14
- multiply the units by the white ratio
14 * 12 = 168
