
We have to <u>evaluate</u> the given <u>expression</u>.

If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.
![\rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} }](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5B1%20-%20%20%5Csin%28x%29%20%5D%7D%7B%5B1%20%2B%20%20%5Csin%28x%29%5D%5B1%20-%20%20%20%5Csin%28x%29%20%5D%7D%20%7D%20)
![\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } }](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5E%7B2%7D%7D%7B1-%20%20%20%5Csin%5E%7B2%7D%20%28x%29%20%7D%20%7D%20)
<u>We know that:</u>


Therefore, <u>the expression becomes:</u>
![\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}}](https://tex.z-dn.net/?f=%20%5Crm%20%3D%20%20%5Csqrt%7B%20%5Cdfrac%7B%5B1%20-%20%20%5Csin%28x%29%5D%5E%7B2%7D%7D%7B%5Ccos%5E%7B2%7D%20%28x%29%7D%7D%20)



Answer:
x=16 or any value less than 16.
Step-by-step explanation:
16x5=80 and subtract 10 you get 70. X has to equal a value that makes the whole left side of the equation "smaller" than the irght side, and 16 or any value less than that would accomplsish this.
Substitute for x.
g(20)= 2(20-4)
g(20)=32.
x=32.
~god bless you!
Answer:
39/25
Step-by-step explanation:
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