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Ray Of Light [21]
3 years ago
6

I need to rewrite d and h without the use of fractional or negative exponents by using radicals, how I do that???

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

The answers written there are correct

What you need to do to solve problems involving fractional or negative exponents is to first break down the exponent. It could be the product of many exponents that are easier to deal with on their own.


If the exponent is negative it can be rewritten as a reciprocal

If the exponent is negative divide it by -1 and divide 1 by what remains

e.g. x^-1/5

     divide -1/5 by -1 and you have 1/5, rewrite it as 1/(x^1/5)


If the exponent is a fraction it can be written as a radical

Make sure the numerator is a positive whole number by rewriting the exponent as a fraction with numerator 1 multiplied by an integer

e.g. x^2/11

      2/11 is the same as 1/11 x 2

     x^(1/11 x 2)

If we call the denominator n then a number with a fractional exponent can be written as the nth root of that number


Hope this helps ^-^




jolli1 [7]3 years ago
3 0

Answer:

The pencil marks on your page show you exactly how to do that.

Step-by-step explanation:

Take advantage of two rules of exponents:

\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}

(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}

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Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:
Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side  that is  ().

Therefore the required interval form is

[-6,-2)U(-2,3)

As we see that () are used with -2 and 3 . And that's the required interval form .

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Step-by-step explanation:

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What is the value of x in the equation 2/3
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Answer:

N/A

Step-by-step explanation:

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6 0
3 years ago
Please show full solutions! WIll Mark Brainliest for the best answer. <br><br> SERIOUS ANSWERS ONLY
Ierofanga [76]

Answer:

  • vertical scaling by a factor of 1/3 (compression)
  • reflection over the y-axis
  • horizontal scaling by a factor of 3 (expansion)
  • translation left 1 unit
  • translation up 3 units

Step-by-step explanation:

These are the transformations of interest:

  g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k

  g(x) = f(x) +k . . . . vertical translation by k units (upward)

  g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis

  g(x) = f(x-k) . . . . . horizontal translation to the right by k units

__

Here, we have ...

  g(x) = 1/3f(-1/3(x+1)) +3

The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:

  • vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
  • reflection over the y-axis . . . 1/3f(-x)
  • horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
  • translation left 1 unit . . . 1/3f(-1/3(x+1))
  • translation up 3 units . . . 1/3f(-1/3(x+1)) +3

_____

<em>Additional comment</em>

The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.

The horizontal transformations could also be described as ...

  • translation right 1/3 unit . . . f(x -1/3)
  • reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)

The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.

8 0
2 years ago
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