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melisa1 [442]
3 years ago
6

What is the solution to the linear equation? (2/3)x-1/2=1/3+(5/6)x

Mathematics
2 answers:
Marianna [84]3 years ago
5 0

x

=

−

5

Explanation:

2

x

3

−

1

2

=

1

3

+

5

x

6

or

4

x

6

−

1

2

=

1

3

+

5

x

6

or

5

x

6

−

4

x

6

=

−

1

3

−

1

2

or

x

6

=

−

5

6

or

x

=

−

5

bija089 [108]3 years ago
3 0

Answer:

x=-5

Step-by-step explanation:

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Hey mathematicians ! Can anyone help me with these problems please ! Will give brainly !
MariettaO [177]

Answer:

15)alternate exterior, 16) corresponding angles 17) alternate exterior 18) same side interior

19) alternate interior

5 0
2 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
Ayo helppp ill give u anthing
kicyunya [14]

Answer:

16.9 m

Step-by-step explanation:

Start with a half a circle. The central angle of a semicircle is 180 deg.

Now subtract 21 deg on each side.

180 - 21 - 21 = 138

The central angle is 138 deg.

The radius is 7 m.

Now we use the formula for the length of an arc of a circle given the radius of the circle and the central angle of the arc.

s = \dfrac{n}{360^\circ}2 \pi r

s = \dfrac{138^\circ}{360^\circ}2(3.14159)(7~m)

s = 16.9~m

4 0
3 years ago
Which statement is most likely to be true? the ages of the mackerels are the most dispersed from the team’s mean. the ages of th
MakcuM [25]

The ages of the Stars are the most dispersed from the team’s mean

<h3> Which statement is right?</h3>

Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data.

Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion.

In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true

To know more about standard deviation follow

brainly.com/question/475676

6 0
2 years ago
Please help me.<br> Round 34,699 to the nearest ten thousand. ASAP
harina [27]
Your number is 34,699 right and if anything is 5000 or over round ahead so it is 30,000
7 0
3 years ago
Read 2 more answers
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