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kotegsom [21]
3 years ago
12

The actions of what nation inspired HoChiMinh to challenge their colonial authority in Vietnam? A) China B) France C) Soviet Uni

on D) United States
Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0
France is the nation that inspired HoChiMinh to challenge their colonial authority in Vietnam. 
postnew [5]3 years ago
7 0

Option B, France is the correct answer..

The French turned Vietnam into their colony in 1887 and ruled oppressively over the Vietnamese, interfered in their social and religious affairs and drained their resources. These actions of France inspired HoChiMinh to turn against the French colonial authority and he succeeded in eliminating them from Vietnam in 1945.

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It is associative property

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The producer of certain medicine claims that it’s bottling
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Answer:

it depends if he's  bottling it or not

Step-by-step explanation:

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3 years ago
The amount of chlorine in a swimming pool is proportional to the volume of water. The pool has 2.5 milligrams of chlorine per li
stira [4]

Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

The chlorine per liter of water in the pool is 2.5 milligrams.

The  volume of water in the swimming pool is 8000 gallons.

Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be x.

The gallons of water in the swimming pool = 8000.

The milligrams of chlorine per liter of water in the pool = 2.5.

According to question, the amount of chlorine in the swimming pool is proportional to the volume of water.

So, 2.5 mg of chlorine is equivalent to 1 liter.

Thus, x is equivalent to 8000.

Now, to get the quantity of chlorine by using cross multiplication method:

\frac{2.5}{1} =\frac{x}{8000}

<em>By cross multiplying we get:</em>

20000=x\\\\x=20,000\ mg.

Therefore, there are 20,000 milligram chlorine in the pool.

6 0
3 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

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3 years ago
How many terms are in the expression 5x^2-3x+2?
Jlenok [28]

There are 3 terms, 5x^2, -3x, and 2

6 0
3 years ago
Read 2 more answers
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