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3 years ago

In the above figure, AE = 2, CE = 3, and DE = 4. What is the length of BE?

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

5 0

Answer:

C. 6

Step-by-step explanation:

The product of the lengths of the segments of the chord is a constant.

AE·BE = DE·CE

2·BE = 4·3 . . . . . . .fill in the given numbers

BE = 12/2 = 6 . . . . divide by the coefficient of BE

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3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A

gtnhenbr [62]

Answer:

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Step-by-step explanation:

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To find: The elements in the set $A \cup C$ .

Solution:

We have,

$\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$

$\text{A}=\left \{\text{q, s, u, w, y} \right \}$

$\text{B}=\left \{\text{q, s, y, z} \right \}$

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$

Now, $A \cup C$ will contain all the elements in the set $A$ and all the elements in set $C$ .

So, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

Hence, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

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