You work it backwards.
-- If there were 4 children and each child got 4 pieces,
then the children got (4 x 4) = 16 pieces altogether.
-- That's what was left after he took 2 pieces for himself.
So he started with (16 + 2) = <em>18 pieces</em>.
The correct answer is C
to get 5 to 100, multiply by 20, so multiply 3 by 20 as well.
Y=mx+b
Y= -14(x-5)+4
Y= -14x+70+4
Y= -14x+74
Plot (0,74)
Then move down 14 then over left 1
Answer:
a) The probability that at least 3 months elapse before the first earthquake of destructive magnitude occurs is P=0.7788
b) The probability that at least 7 months elapsed before the first earthquake of destructive magnitude occurs knowing that 3 months have already elapsed is P=0.7165
Step-by-step explanation:
Tha most appropiate distribution to model the probability of this events is the exponential distribution.
The cumulative distribution function of the exponential distribution is given by:

The destructive earthquakes happen in average once a year. This can be expressed by the parameter λ=1/year.
We can express the probability of having a 3 month period (t=3/12=0.25) without destructive earthquakes as:

Applying the memory-less property of the exponential distribution, in which the past events don't affect the future probabilities, the probability of having at least 7 months (t=0.58) elapsed before the first earthquake given that 3 months have already elapsed, is the same as the probability of having 4 months elapsed before an earthquake.

