Factor by grouping 4ax-10bx+6ay-15by

1 answer:

3 0

Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get

(4ax-10bx)+(6ay-15by)

Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)

Not sure how to explain this step in words but so do this

(2x+3y)(2a-5b)

The solution is (2x+3y)(2a-5b)

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In two or more complete sentences, explain whether the sequence is finite or infinite. Describe the pattern in the sequence if i

levacccp [35]

The sequence is given as follow
$3a$ , $3 a^{2}b,3 a^{3} b^{2} , 3 a^{4} b^{3}$

When finding the pattern of a sequence, we can try to work out whether there is a common difference or a common ratio between each term. We try by finding a common ratio

$\frac{3 a^{2}b }{3a} =ab$
$\frac{3 a^{3 b^{2} } }{3 a^{2}b }=ab$
$\frac{3 a^{4} b^{3} }{3 a^{3} b^{2} }=ab$

The term to term rule is multiplied by $ab$

The $5^{th}$ term is given $3 a ^{4} b^{3}$ × $ab=3 a^{5} b^{4}$

The $6^{th}$ term is given by $3 a^{5} b^{4}$ × $ab=3 a^{6} b^{5}$

8 0

3 years ago

if the cost of a movie ticket now averages $11.50 , interpret the meaning of the expression 11.50(1.083)

LUCKY_DIMON [66]

I believe the correct expression is: 11.50(1.083)^t where t is the time.

Now, we are given that the average price of the ticket is $11.5
The given expression means that this average value is dependent on the variable t. Therefore, the average price of the ticket increases exponentially with the time with the rate of growth equals 1.083

Now, to better understand this, we will get the price of the ticket at different times:
At t = 1: price = 11.50(1.083)^1 = $12.4545
At t = 2: price = 11.50(1.083)^2 = $13.4882235
At t = 3: price = 11.50(1.083)^3 = $14.60774605
We can notice that the price of the ticket increases exponentially as the time increases.

Hope this helps :)

5 0

3 years ago

Which expression is equivalent to 46 - 2x)?

andrew-mc [135]

Answer:

24-8x

Step-by-step explanation:

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3 years ago

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Mary spent a total of $353.86 for a party. She spent $200.51 on food, plus an additional $30.67 for each hour of the party. How

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