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kirill115 [55]
3 years ago
13

Factor by grouping 4ax-10bx+6ay-15by

Mathematics
1 answer:
Digiron [165]3 years ago
3 0
Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get

(4ax-10bx)+(6ay-15by)

Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)

Not sure how to explain this step in words but so do this

(2x+3y)(2a-5b)

The solution is (2x+3y)(2a-5b)
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lianna [129]

Answer:

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Step-by-step explanation:

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2 years ago
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 49:11 A data set has a maximum of 84, a minimum of 34, a median of 52.5, an upper quartile o
Dahasolnce [82]

Hello!

In a box plot, the edges of the box represent the lower and upper quartiles. The line dividing the box is the median. The left whisker goes from the minimum to the lower quartile, and the right whisker goes from the upper quartile to the maximum.

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4 0
3 years ago
The area of circle K when c=24x^2 pi
Gala2k [10]

Answer:\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }

Step-by-step explanation:

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Switch sides:

24x^2\pi =Kc

divide both sides by 24\pi

\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }

simplify:

x^2=\frac{Kc}{24\pi }

x^2=\frac{Kc}{24\pi }x=\sqrt{\frac{Kc}{24\pi }},\:x=-\sqrt{\frac{Kc}{24\pi }}

answer:x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }

i hope it's help!

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sp2606 [1]

Answer:

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Step-by-step explanation:

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netineya [11]
What are asking for? The solution?
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divide 6 from both sides so n=
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3 years ago
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