I need help asap please

the cost of a phone call lasting 3 minutes 30 seconds was 52.5 cents . at this rate what was the cost of a call lasting 5 minute

Effectus [21]

Answer:

80 cents

Step-by-step explanation:

The easiest place to start for this is to calculate how much it costs per minute of call time. To do this, if we know that it costs 52.5 cents to call for 3.5 minutes, we can divide those two numbers to get how much it costs per minute.

52.5/3.5 = 15

If it costs 15 cents per minute, and we want to know how much it would cost to call for 5.33 (5 and 1/3 of a minute), then we multiply our 15 cents a minute by the number of minutes to get the final cost.

15 x 5.33 = 79.99

Because we can't have 99/100 cents, rounding up to 80 is important to get a proper answer.

6 0

3 years ago

One month,ruby worked 6 hours more than Isaac, and Svetlana worked 4 times as many hours as ruby. Together they worked 138 hours

Fiesta28 [93]

Ruby- 24
Isaac- 18
Svetlana - 96

7 0

3 years ago

3/8 + 2 1/2 <br><br> pls help!!! make sure to show work. thanks :)

dimaraw [331]

Answer:

2 7/8

Step-by-step explanation:

Let's convert to common denominator

3/8 = 3/8

2 1/2 = 2 4/8

3/8 + 2 4/8 = 2 7/8

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

2 years ago

What is the z-score of a newborn who weighs 4,000 g?.

vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

$X \sim N(\mu, \sigma)$

(X is following normal distribution with mean $\mu$ and standard deviation $\sigma$ )

then it can be converted to standard normal distribution as

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

$P(Z \leq z) = P(Z < z) )$

Also, know that if we look for Z = z in z tables, the p value we get is

$P(Z \leq z) = \rm p \: value$

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

X = weights of newborns for some considered system (in grams)
$\mu$ = mean weight of newborns (in grams)
$\sigma$ = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

$z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}$

Thus, the z-score of the considered newborn having 4,000 g weight is $\dfrac{4000 - \mu}{\sigma}$

Learn more about z-scores here:

brainly.com/question/13299273

3 0

2 years ago

Trevor season 8 red birds. He sees 5 more red birds than bluebirds. How many bluebirds does Trevor see?

aliya0001 [1]

Answer:

3 blue birds

Step-by-step explanation:

8-5=3

7 0

3 years ago