All categories

2 years ago

1- 1/4 + 2/5= please help

Mathematics

2 answers:

zlopas [31]2 years ago

4 0

Answer:

1.15:)

Step-by-step explanation:

ZanzabumX [31]2 years ago

4 0

Answer:

1.15

Step-by-step explanation:

You might be interested in

PLS HELP ME GUYS ITS MY LAST QUESTION IN GEOMETRY

aliina [53]

Answer:

Example = ( 12, 1 )

Step-by-step explanation:

There are many possible solutions to this equation, and all you would have to do to determine the ordered pair, is satisfy the following criteria -

$x - 6y = 6,\\- 6y = - x + 6,\\y = 1 / 6x - 1$

Take a look at a graph of the line y = 1 / 6x - 1. Any ordered pair that lies on this line is a solution to the equation. The " criteria " is that the ordered pair must lie on this line. Let me give you an example, ( 12, 1 ).

<u><em>Hope that helps!</em></u>

7 0

2 years ago

GF GF

Lera25 [3.4K]

Answer:

Reflexive property of congruence.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

20 POINTS!

alukav5142 [94]

I think it was √(a^2+b^2. I think.

8 0

2 years ago

Frank has a 2-digit number on his baseball uniform. The number is a multiple of 10 and has 3 for one its factors. What three num

Effectus [21]

30, 60, 90

a. What possible jersey numbers does Frank wear.
b. its a multiple 10 and has 3 for one of its factors and its a 2-digit number,
c. By eliminating all the incorrect answers?
d. Number on, 10, 3, and frank could have 30, 60, or 90.

6 0

2 years ago

Estimates of the number of cells in the human body vary over an order of magnitude. Indeed, the precise number varies from one

Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰; b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

$\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}$

b) No. of cells in 1 L

$\text{No. of cells} = \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}$

7 0

3 years ago