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SCORPION-xisa [38]
3 years ago
10

HELP!

Mathematics
1 answer:
Vesna [10]3 years ago
4 0
A(n)=a+(n-1)d
A(40)= -1+(40-1)-4
A(40)= -1+39(-4)
A(40)= -1+(-156)
A(40)= -157
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P(z

And replacing the value obtained we got:

z=-1.282

And if we solve for a we got

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Step-by-step explanation:

Let X the random variable that represent the average home prices of a population, and for this case we know the distribution for X is given by:

Where \mu=410000 and \sigma=65000

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.90   (a)

P(X   (b)

We want to find a value who accumulate 0.10 of the area on the left and 0.90 of the area on the right of the normal standard distributon and for this case it's z=-1.282

And using the distribution for the sample mean we can do this:

P(X  

P(z

And replacing the value obtained we got:

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And if we solve for a we got

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