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kipiarov [429]
3 years ago
13

Question below. I need answer asap plsss

Mathematics
2 answers:
podryga [215]3 years ago
7 0

Answer:

y = 1/2x + 4

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
4 0

Answer:

y = 1/2x + 4

Step-by-step explanation:

To find the 1/2 you can see that is is between the box, and cannot be negative because it is going up not down. To find y-interceptive, you start where the line starts and until you hit a y value; which is 4.

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-xv-2v+14x+7x^2<br><br> Factor By grouping
RoseWind [281]
The answer to the question

3 0
3 years ago
A die has 12 faces numbered 1 through 12. On the die, 5 of the faces show prime numbers, so the theoretical probability of rolli
Georgia [21]

Answer:

5/12 * 300 = 125 times

explain:

I hope this answer can help

3 0
3 years ago
Complete the work to find the dimensions of the rectangle. x(x – 3) = 10 x2 – 3x = 10 x2 – 3x – 10 = 10 – 10 (x + 2)(x – 5) = 0
Norma-Jean [14]

Answer:

Length =5

Width = 2

Step-by-step explanation:

Given

Length =x

Width = x -3

Area = 10

x(x-3) =10

See comment for missing part of the question

Required

Complete the expression to determine the dimension of a rectangle

We have:

x(x-3) =10

Open bracket

x^2 -3x = 10

Equate to 0

x^2 -3x - 10 =0

Expand

x^2 + 2x - 5x - 10 = 0

Factorize

x(x + 2) - 5(x + 2) = 0

Factor out x + 2

(x  - 5)(x + 2) = 0

Solve for x

x - 5 = 0 or x + 2 = 0

x = 5 or x = -2

The value of x cannot be negative

So:

x  = 5

Recall that:

Length = x

Width = x - 3

So:

Length =5

Width = 2 ---- i.e. 5 - 3

6 0
3 years ago
180 product of a prime factor using indices
zvonat [6]
Start with 180. 
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>

<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>

<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>

<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>

<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>

<span>Once you end up with a quotient of "1" you're done. </span>

<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
5 0
3 years ago
Read 2 more answers
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
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