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kipiarov [429]
3 years ago
13

Question below. I need answer asap plsss

Mathematics
2 answers:
podryga [215]3 years ago
7 0

Answer:

y = 1/2x + 4

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
4 0

Answer:

y = 1/2x + 4

Step-by-step explanation:

To find the 1/2 you can see that is is between the box, and cannot be negative because it is going up not down. To find y-interceptive, you start where the line starts and until you hit a y value; which is 4.

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What is the measure of Angle J K L?
ivanzaharov [21]

Answer:

97 degrees

Step-by-step explanation:

180 degrees minus 83 degrees is 97 degrees

3 0
3 years ago
Read 2 more answers
Solve the equation <br> -2(2x+3)+11=11-3x
Nadusha1986 [10]

First, distribute -2 to all terms within the parenthesis

-2(2x) = -4x

-2(3) = -6

-4x - 6 + 11 = 11 - 3x

SImplify. Combine like terms

-4x (-6 + 11) = 11 - 3x

-4x + 5 = 11 - 3x

Isolate the x. Add 3x to both sides, and subtract 5 from both sides

-4x (+3x) + 5 (-5) = 11 (-5) - 3x (+ 3x)

-4x + 3x = 11 - 5

Simplify

-x = 6

Isolate the x. Divide -1 from both sides

-x/-1 = 6/-1

x = -6

-6 is your answer

hope this helps

7 0
3 years ago
Helpppppp ASAP !!!!!
blondinia [14]

Answer:

{ \bf{c). \: g(x) =  {(x - 3)}^{2} }}

4 0
3 years ago
For the geometric sequence, what is the 7th term 8, 12, 18, 27,
larisa [96]
 The answer would be<span>27 * 3/2 = 40.5</span>
4 0
4 years ago
Read 2 more answers
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
denis-greek [22]
Let x be the distance from the left wall to the laser source and y the distance form the right wall to the laser source. 

We can use the cosine trigonometric function in the smaller triangle to relate the adjacent side of the angle and the hypotenuse; then we can solve for x:
cos( \alpha )= \frac{adjacent.side}{hypotenuse}
cos(60)= \frac{x}{40}
x=40cos(60)
x=20m

We can use the tangent trigonometric function in the larger triangle to relate the opposite side of the angle and its adjacent side; then we can solve for y:
tan( \alpha )= \frac{opposite.side}{adjacent.side}
tan(45)= \frac{80}{y}
y= \frac{80}{tan(45)}
y=80m

Now we can add both distances:
20m+80m=100m

We can conclude that <span>the distance between the walls is 100 m.</span>

8 0
4 years ago
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