Fraction 1 whole minus 3 8 ths

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

4 years ago

Triangle ABC is translated to image A′B′C′. In this translation, A(5, 1) maps to A′(6, –2). The coordinates of B′ are (–1, 0). T

Phantasy [73]

Answer:

B (-2, 3)

Step-by-step explanation:

Just took quiz

4 0

3 years ago

Read 2 more answers

Find the area of a triangle whose height is 2x and base is 2x + 2.

wel

Answer: $2x^{2}+2x$

Step-by-step explanation:

1. You must apply the formula for calculate the area of a triangle, which is shown below:

$Area=\frac{base*height}{2}$

2. You know the height and the base, which are given in the problem. Then, you only need to substitute them into the equation shown above and simplify it, as following:

$Area=\frac{2x(2x+2)}{2}$

$Area=x(2x+2)\\Area=2x^{2}+2x$

3 0

3 years ago

Solve 3/10 n-3 1/5 = -1 1/5

Ivahew [28]

Use socrative to get your math questions it helps a lot i promise

7 0

3 years ago

Write an equation in point – slope form from the line through the given point with the given slope. (-10, -1); m=-1

Alexxandr [17]

Answer:

y = -x - 11

Step-by-step explanation:

We know the equation must be: y = -x + c

However we do not know what "C" is. If we plug in our x and y values then we can find out the value of C.

So:

-1 = -(-10) + c

-1 = 10 + c

so c = -11

So our equation is:

y = -x - 11

5 0

3 years ago