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ASHA 777 [7]
3 years ago
9

Can someone help me with this question

Mathematics
1 answer:
Virty [35]3 years ago
4 0
5/6 of a mile because 5/12+5/12=10/12 or 5/6
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Can someone please help me solve this math problem, please? Thanks.
Ganezh [65]
If you use FOIL to multiply these two brackets, it will lead you what is exactly written (xa+xb+ya+yb)


so it is correct

A
4 0
3 years ago
joey gets hired with a $100 signing bonus for a job that makes $15 an hour. Sarah does not get a singing bonus but makes $17 an
KATRIN_1 [288]
The only difference I see is that he would have money so...
8 0
3 years ago
A boy has only dimes and quarters in his piggy bank. if he has 70 coins worth 12 dollars and 40 cents altogether, how many quart
dlinn [17]

Let us bear in mind the equivalent value of these coins: 

One dime = $0.10 

One quarter = $0.25 

Let x = number of dimes 

        y<span> = number of quarters</span> 

Since the boy has 70 coins in total, we can say that: 

<span>x + y = </span><span>70 </span>(can be written as x = 70 – y) 

Since the boy has a total of $12.40, we can say that: 

0.10x + 0.25y = 12.40 

To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y) 

0.10(70 – y) + 0.25y = 12.40 

7 – 0.10y + 0.25y = 12.40 

0.15y = 5.40 

y = 36 

X = 70 – 36 

X = 34 

Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span> 

34 dimes = $3.40 

36 dimes = $9.00 

<span>Total           </span><span>$12.40</span>

7 0
3 years ago
Read 2 more answers
A falcon flies 300 kilometers per hour. A goose flies 140 kilometers per hour. If a falcon and a goose each fly for 2 hours, how
Mila [183]

Answer:

320

Step-by-step explanation:

Distance covered by falcon in 2 hours=300*2=600 km

Distance covered by goose in 2 hours=140*2=280 km.

Falcon flew 600-280=320 km more than goose

7 0
3 years ago
The surface area of the prism below is 264 square units . Find the missing dimensions of this prism. ( picture is in the picture
nignag [31]

Answer:

The missing dimension is 4 units.

Step-by-step explanation:

In the given prism,

Of all the surfaces,

There are three rectangular surfaces and two triangular surfaces

<h2>Analyzing areas of rectangular surfaces:</h2>

1)The two rectangles with dimensions of 15 units and 5 units:

The area of each rectangle = Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 5 units.

Area of each rectangle = 15\times 5 ;

Area of each rectangle = 75 square units.

Sum of areas of the two rectangles = 2\times 75

Sum of areas of the two rectangles = 150 square units (equation 1)

2) The rectangle with the dimensions 15 units and 6 units:

The area of thus rectangle=  Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 6 units.

Area of the rectangle = 15\times 6 ;

Area of the rectangle = 90 square units. (equation 2)

From equation 1 and equation 2,

Therefore sum of areas of all rectangles in the prism = 150 + 90

Sum of areas of rectangles = 240 square units.

We also know,

Total surface area of the prism = Sum of areas of triangles + Sum areas of rectangles

Given, Total surface area of prism = 264 square units.

Therefore from the formula,

Sum of areas of triangles = Total surface area - sum of areas of reactangles

Sum of areas of triangles = 264 - 240

Sum of areas of triangles = 24 square units. (equation 3)

Let the missing dimension be 'h units'

<h2>Calculating sum of areas of triangles:</h2>

From diagram,both triangles are congruent,hence have the same area

Area of a triangle = \frac{1}{2}\times base\times height

From diagram,

Base = 6 units,

Height = h units.

Area of a triangle =\frac{1}{2}\times 6\times h = 3h square units.

Sum of the areas of both triangles = 3h+3h = 6h square units.

Using equation 3, we get

6h = 24;

h = \frac{24}{6}

Therefore,

h = 4 units.

Therefore,

The missing dimension is 4 units.

4 0
3 years ago
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