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Svetllana [295]
3 years ago
8

Find the missing side of the triangle

Mathematics
1 answer:
Ede4ka [16]3 years ago
6 0
Area=(1/2)bh
b=legnth of base
h=legnth of height

we are given
b=3 and 1/4
area=12 and 2/5

covert everybody to improper fraction

b=3 and 1/4=3+1/4=12/4+1/4=13/4
area=12 and 2/5=12+2/5=60/5+2/5=62/5

area=(1/2)bh
62/5=(1/2)(13/4)h
62/5=(13/8)h
times 8/13 both sides (13/8 times 8/13=104/104=1)
496/65=h
7 and 41/65 is answer



7 and 41/65 units or
496/65 units
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Step-by-step explanation:

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3-4 litros de jugo de frutilla 1 y 1-2 litros de jugo de manzana 1-8 litro de jugo consentrado de limón . 1 y 1-2 litro de agua.
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Answer:

Hay 3,875 litros de jugo multifrutal.  

Step-by-step explanation:

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Step-by-step explanation:

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Salsk061 [2.6K]

Answer:

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Step-by-step explanation:

We want to

4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} }  - x \sqrt[3]{2x} )

We expand to obtain:

4x \sqrt[3]{4 {x}^{2} }  \times 2 \sqrt[3]{32 {x}^{2} }  -4x \sqrt[3]{4 {x}^{2} } \times  x \sqrt[3]{2x} )

We now simplify

8x \sqrt[3]{4 {x}^{2}  \times 32 {x}^{2} }    -4 {x}^{2}  \sqrt[3]{4 {x}^{2}  \times 2x}

We multiply the radicand

8x \sqrt[3]{64 \times {x}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{8 {x}^{3}}

Or

8x \sqrt[3]{ {(4x)}^{3}  \times 2x }    -4 {x}^{2}  \sqrt[3]{{(2x)}^{3}}

We take cube root to get:

8x  \times 4x\sqrt[3]{ 2x }    -4 {x}^{2}  \times 2x

We multiply out to get:

32 {x}^{2} \sqrt[3]{ 2x }    -8{x}^{3}

6 0
3 years ago
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