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Over [174]
4 years ago
10

How do you solve:18(18)=x(x+15)

Mathematics
1 answer:
ehidna [41]4 years ago
7 0
Hello!

18(18)=x(x+15)

The parentheses indicate multiplication; the 18(18) on the left side of the equation is 18 * 18. On the right side of the equation, you have x(x + 15); to simplify this, you would distribute the x--that means multiply each term inside the parentheses by x. This is the Distributive Property: a(b + c) = ab + ac. Let's do that.

18(18)=x(x+15)
324= x^{2} +15x

Now, you can subtract 324 from each side to set the equation equal to 0.

324= x^{2} +15x
324-324= x^{2} +15x-324
0= x^{2} +15x-324

This is a quadratic equation; to solve it, we may factor (if the equation is able to be factored) or we can use the Quadratic Formula. Let's see if we can factor. To factor, find two numbers whose sum is 15 and whose product is -324. Since 324 is negative, we know one of the numbers is negative and one of the numbers is positive (a negative times a positive is always negative), and that means one of the numbers is greater than 15...

27 - 12 = 15
27 * -12 = -324

The factored polynomial is: (x + 27)(x - 12).

To find its solutions, set the factors equal to 0 and solve for x.

x + 27 = 0
x = -27

x - 12 = 0
x = 12

Answer:
The solution of 18(18)=x(x+15) is -27 and 12.
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<h2>Answer with explanation:</h2>

Let p be the population proportion  of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

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Set hypothesis to test :

H_0: p=0.39\\\\H_a :p\neq0.39

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Sample proportion : \hat{p}=\dfrac{466}{1055}=0.441706161137\approx0.44

Critical value for 95% confidence : z_{\alpha/2}=1.96

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Complete the work to find the dimensions of the rectangle. x(x – 3) = 10 x2 – 3x = 10 x2 – 3x – 10 = 10 – 10 (x + 2)(x – 5) = 0
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Answer:

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Width = 2

Step-by-step explanation:

Given

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See comment for missing part of the question

Required

Complete the expression to determine the dimension of a rectangle

We have:

x(x-3) =10

Open bracket

x^2 -3x = 10

Equate to 0

x^2 -3x - 10 =0

Expand

x^2 + 2x - 5x - 10 = 0

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Factor out x + 2

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Solve for x

x - 5 = 0 or x + 2 = 0

x = 5 or x = -2

The value of x cannot be negative

So:

x  = 5

Recall that:

Length = x

Width = x - 3

So:

Length =5

Width = 2 ---- i.e. 5 - 3

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