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valentina_108 [34]
3 years ago
6

Which option lists am expression that is not equivalent to 4^2/3

Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

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What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375
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<u>Answer:</u>

<u><em>426</em></u>

<u />

<u>Explanation:</u>

To find the median number in a set of data start by reordering the data from least to greatest.

<em>original data set:</em>

<em>593, 588, 540, 434, 420, 398, 390, 375</em>

<em />

<em>data set from least to greatest:</em>

<em>375, 390, 398, 420, 434, 540, 588, 593</em>

<em />

Next, you would usually just have to find the middle number in the data set and that would be your median. However, this data set has no one number that is directly in the middle. So, we will add both middle numbers together and then divide our answer by two.

<em>375, 390, 398, </em><em>420, 434</em><em>, 540, 588, 593</em>

<em />

<em>420 + 434 = 854</em>

<em />

<em>854 ÷ 2 = 426</em>

<em />

Therefore, the median of the given data set is <em><u>426.</u></em>

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