Answer:
The graph is attached.
Step-by-step explanation:
The graphs:
f(x) = x + 1 where x < 0
f(x) = 2 where 0 ≤ x ≤ 1
f(x) = x where x > 1
Vi = 56
Vf = 56 + 7(3) = 56 + 21 = 77
THe average is (Vf + Vi)/2
(77 + 56)/2 = 133/2 = 66.5 m/s
The wind is blowing at the rate of 4 miles per hour
<h3>Speed and distances</h3>
The formula for calculating speed is expressed as:
Speed = Distance/Time
Given the following parameters
Speed of airplane = 18 miles per hour
Speed in wind = 2.2 * 10 = 22 miles/hr
Speed of the wind = 22 - 18
Speed of the wind = 4mi/hr
Hence the wind is blowing at the rate of 4 miles per hour
Learn more on speed here: brainly.com/question/4931057
Answer:
The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.
Step-by-step explanation:
We consider "lack of control by at least the third point plotted" if at least one of the three first points is over the UCL or under the LCL.
The probability of one point of being over UCL=104 is:
The probability of one point of being under LCL=96 is:
Then, the probability of exhibit lack of control is:
The probability of having at least one point out of control in the first three points is:
The probability that the control chart would exhibit lack of control by at least the third point plotted is P=0.948.
16.2 + -8.4 = 7.8 is your Answer