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3 years ago

Find the unknown digit to make each statement true 5.345>5.34_>5.343

1 answer:

3 0

The unknown digit is 4 because you must have a number (in the space) that is less than five and more than four because looking at a number like
10 9 8 7 6 5 4 3 2 1 the only while number in between 5 and 3 is 4.

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What is a/9 =-4 I really need help on this one

pashok25 [27]

The answer I believe is -36

5 0

3 years ago

Read 2 more answers

Robert drew a parallelogram with 2 55 degree angles. What are the measures of the 2 other angles? Both of the angles have to be

Licemer1 [7]

Angles in a parallelogram have to equal 360.

Let x represent the measurement of the unknown angle.

2(55) + 2x = 360
110 + 2x = 360
2x = 250
x = 125

125 degrees

5 0

3 years ago

4x-5,4(x-5),4(x+5) drag the phrases into each box to match each expression five sang the sum of four and number five more than t

jeyben [28]

Answer:

4x-5= 5 less than the product of 4 and a number. 4 (x-5)= The product of 4 and the difference of a number and 5. 4(x+5) = The product of 4 and the sum of a number and 5.

Step-by-step explanation:

I took the test online in K12 and when I reviewed it said that those are the correct answer.

8 0

4 years ago

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

6 0

3 years ago

Solve this system by substitution. y = 5x - 15 y = 2x - 6 *Remember to write your answer as a coordinate point (x,y Solve this s

oksano4ka [1.4K]

5x - 15 = 2x - 6
3x = 9
x = 3
Y = 5(3) - 15
Y = 0
(3,0)

7 0

3 years ago