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Ierofanga [76]
3 years ago
7

Find all the real cube roots of 0.000027.

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
The real cube root is 0.03 because...
(0.000027)^1/3 = (27 x 10^-6)^1/3 = 3 x 10^-2 = 0.03
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M<1 =40-4x; and m<2=50-8x
matrenka [14]
What's the question?
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3 years ago
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

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3 years ago
Write the equations for the graphs below (worth 5 points) ​
serg [7]
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10) y= 1/2x - 2
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I found this by using y=mx+ b
3 0
3 years ago
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tangare [24]
It's just asking for the gradient basically
150/3 = 50
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7 0
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What is the total paid back on a loan of $1,500 with an interest rate of 3.74% for 2 years?
zheka24 [161]

Answer:

1612.2

Step-by-step explanation:

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5 0
3 years ago
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