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lutik1710 [3]
4 years ago
5

What's the evaluation of log5^125

Mathematics
2 answers:
Rama09 [41]4 years ago
8 0
3.6 if the question is log(5)^125 or 87.37 if the question is log(5^125)
den301095 [7]4 years ago
3 0
3. I did this on my calculator, by pressing MATH, APLHA, MATH. Then I inserted the information
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Find the? mean, median, and mode of the set of values. Age? (years) 11 12 13 14 15 16 17 Frequency 7 9 11 10 9 4 3 Find the mean
rewona [7]

Answers:

Mean = 13.55

Median = 13

Mode = 13

====================================================

Explanations

Mean:

To get the mean, multiply the ages with their corresponding frequencies. Then add up the results. I show this in the attached image below. The highlighted yellow cell is the sum of the x*y column (x = age, y = frequency). This value is 718.

Once you get to 718, you divide this over the total frequency which is 7+9+11+10+9+4+3 = 53 (so there is 53 people).

The mean is therefore 718/53 = 13.5471698113208 which rounds to 13.55

----------------------

Median:

The median is the middle most value. There are 53 values here (add up the frequencies), so the midpoint is at slot 53/2 = 26.5 = 27. The first 26 values are below the median, and the last 26 values are above the median leaving 53-26-26 = 53 - 52 = 1 value in the very exact center.

Add up the frequencies starting from 7 then to 9, etc until you get to 27. So we have

7+9 = 16 which isn't 27

7+9+11 = 16+11 = 27 perfect, we landed on 27

This means that the last copy of 13 is in slot 27. This is because the last frequency added (11) corresponds to the age 13.

That is why the median is 13

----------------------

Mode:

The mode is the most frequent value. Simply record the age that has the highest frequency. In this case, the highest frequency is 11 which corresponds to age 13, pointing to the mode being 13.


5 0
3 years ago
Can anyone help me with these: 65mm=?cm, 600cm=?m , 800cm=?m
stira [4]
65mm \to6.5cm \\\\ 600cm\to6m\\\\800cm\to8m
7 0
4 years ago
Read 2 more answers
Here are the shopping times (in minutes) of ten shoppers at a local grocery store.
d1i1m1o1n [39]

The frequency which is to filled in the table is 3,1,2,4.

Given  shopping time of ten shopkeeper: 36,20,32,18,20,33,28,34,37,23.

We have to complete the frequency in the table. Frequency of something is the number of times that number is coming.

Shopping time is given as 36,20,32,18,20,33,28,34,37,23.

Intervals for which frequency is given is 18 to 22, 23 to 27, 28 to 32, 33 to 37.

Numbers in the range 18 to 22=18,20,23 therefore 3

Numbers in the range 23 to 27=23 therefore 1

Numbers in the range 28 to 32=32 , 28  therefore 2

Numbers in the range 33 to 37=36, 33, 37, 34 therefore 4.

Hence the frequency which is to filled are 3,1,2,4.

Learn more about  frequency at brainly.com/question/254161

#SPJ10

8 0
2 years ago
Arc AB is 1/6 of the circumference of a circle. What is The radian measure of the central angle?
Novosadov [1.4K]

Answer:

It’s b pie over 3

Step-by-step explanation:

I just know this I did the work

3 0
4 years ago
Read 2 more answers
Simplify \sqrt{0.81}
olchik [2.2K]

Answer:

Square root of .81 = .9

7 0
4 years ago
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