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Citrus2011 [14]
3 years ago
14

Give the values of a, b, and c needed to write the equation's standard form. 1/4x^2+5=0

Mathematics
2 answers:
yarga [219]3 years ago
5 0
<span>In general a quadratic equation form is ax^2 + bx+ c = 0 --eqn 1 Solution: therefore in the given equation 1/4x^2+5=0 it can be rewritten as x^2+0x +20=0; and this is the standard form therefore comparing with eqn 1 we get, a=1; b=0 ; c=20 Ans : - a=1; b=0 ; c=20 to obtain x, the quadratic formula is x = {â’b (+-) âš(b2 â’ 4ac)} / 2a x= 2i 5^(1/2) [where i= {-1 ^(1/2)}]</span>
Pavel [41]3 years ago
4 0
The equation in its standard form is written as followsax ^ 2 + bx + c = 0
 To find the values of a, b, c we must compare the given equation with the standard equation. Comparing we have:
 ax ^ 2 + bx + c = 0
 1 / 4x ^ 2 + 5 = 0
 Therefore the values of a, b, c are
 a = 1/4
 b = 0
 c = 5
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A polynomial can have:

constants (like 3, −20, or ½)
variables (like x and y)
exponents (like the 2 in y2), but only 0, 1, 2, 3, ... etc are allowed
that can be combined using addition, subtraction, multiplication and division ...

... except ...

... not division by a variable (so something like 2/x is right out)

So:

A polynomial can have constants, variables and exponents,
but never division by a variable.

Also they can have one or more terms, but not an infinite number of terms.

These are polynomials:

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These are not polynomials

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2/(x+2) is not, because dividing by a variable is not allowed
1/x is not either
√x is not, because the exponent is "½" (see fractional exponents)


But these are allowed:

x/2 is allowed, because you can divide by a constant
also 3x/8 for the same reason
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Have a great day!
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