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Citrus2011 [14]
3 years ago
14

Give the values of a, b, and c needed to write the equation's standard form. 1/4x^2+5=0

Mathematics
2 answers:
yarga [219]3 years ago
5 0
<span>In general a quadratic equation form is ax^2 + bx+ c = 0 --eqn 1 Solution: therefore in the given equation 1/4x^2+5=0 it can be rewritten as x^2+0x +20=0; and this is the standard form therefore comparing with eqn 1 we get, a=1; b=0 ; c=20 Ans : - a=1; b=0 ; c=20 to obtain x, the quadratic formula is x = {â’b (+-) âš(b2 â’ 4ac)} / 2a x= 2i 5^(1/2) [where i= {-1 ^(1/2)}]</span>
Pavel [41]3 years ago
4 0
The equation in its standard form is written as followsax ^ 2 + bx + c = 0
 To find the values of a, b, c we must compare the given equation with the standard equation. Comparing we have:
 ax ^ 2 + bx + c = 0
 1 / 4x ^ 2 + 5 = 0
 Therefore the values of a, b, c are
 a = 1/4
 b = 0
 c = 5
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