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2 years ago

Give the values of a, b, and c needed to write the equation's standard form. 1/4x^2+5=0

2 answers:

5 0

In general a quadratic equation form is ax^2 + bx+ c = 0 --eqn 1 Solution: therefore in the given equation 1/4x^2+5=0 it can be rewritten as x^2+0x +20=0; and this is the standard form therefore comparing with eqn 1 we get, a=1; b=0 ; c=20 Ans : - a=1; b=0 ; c=20 to obtain x, the quadratic formula is x = {â’b (+-) âš(b2 â’ 4ac)} / 2a x= 2i 5^(1/2) [where i= {-1 ^(1/2)}]

Pavel [41]2 years ago

4 0

The equation in its standard form is written as followsax ^ 2 + bx + c = 0
To find the values of a, b, c we must compare the given equation with the standard equation. Comparing we have:
ax ^ 2 + bx + c = 0
1 / 4x ^ 2 + 5 = 0
Therefore the values of a, b, c are
a = 1/4
b = 0
c = 5

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A data set includes 108 body temperatures of healthy adult humans having a mean of 98.3degrees°F and a standard deviation of 0.6

mylen [45]

<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n=106

Sample mean : $\overline{x}=98.3^{\circ}\ F$

Standard deviation : $\sigma= 0.69^{\circ}F$

Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Then , 99% confidence interval estimate of the mean body temperature of all healthy humans will be :-

$98.3\pm (2.576)\dfrac{0.69}{\sqrt{106}}\\\\\approx98.3\pm0.173=(98.3-0.173,\ 98.3+0.173)=(98.127,\ 98.473)$

Since 98.6 is higher than the upper limit of the confidence interval (98.473), then this suggest that the mean body temperature could be lower then 98.6 degrees.

The best estimate of population mean is always the sample mean. $\mu=\overline{x}=98.3^{\circ}\ F$

7 0

3 years ago

Can someone give an explaination please

iren [92.7K]

Answer:

x ≥ -3

x ≤ 3

Step-by-step explanation:

For the first inequality, just add 3 to both sides.

For the second inequality, add 4 to both sides then divide both sides by 3.

3 0

2 years ago

Attachment below algebra helppppp

yKpoI14uk [10]

Answer: second option.

Step-by-step explanation:

In order to solve this exercise, it is necessary to remember the following properties of logarithms:

$1)\ ln(p)^m=m*ln(p)\\\\2)\ ln(e)=1$

In this case you have the following inequality:

$e^x>14$

So you need to solve for the variable "x".

The steps to do it are below:

1. You need to apply $ln$ to both sides of the inequality:

$ln(e)^x>ln(14)$

2. Now you must apply the properties shown before:

$(x)ln(e)>ln(14)\\\\(x)(1)>2.63906\\\\x>2.63906$

3. Then, rounding to the nearest ten-thousandth, you get:

$x>2.6391$

3 0

2 years ago

ACFG is a parallelogram, If AX = 4y + 3 and XF = 2y + 7, find AX.

pashok25 [27]

Answer:

AX=XF

4y+3=2y+7

4y-2y=7-3

2y=4

y=2

then,

AX=4y+3

=4×2+3

=8+3

=11

3 0

3 years ago

Given f(x) = -x – 4, find f(4). I need help

Brums [2.3K]

Answer:

f(4) = -8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = -x - 4

f(4) is x = 4

Step 2: Evaluate

Substitute in x: f(4) = -4 - 4
Subtract: f(4) = -8

5 0

2 years ago