For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Answer:
3
Step-by-step explanation:
3 is the coefficient of c as it is a constant, whereas a and b are variables, subject to change.
Answer: -√1/✓41
Step-by-step explanation:
Let y be the irrational number that will be multiplied by -√41 to get the product that equals 1.
y × (-√41) = 1
We then solve for y, by dividing through with -√41. This will be:
[y × (-√41)]/-√41 = 1/-√41
y = -1/√41
y = -√1/✓41
The irrational number is negative root one over root forty one.
1.25x=1.25 so divided both sides by 1.25 sooo x=1
Yes it is because 2 sides would be the legs while 1 side is the hyptonuese so in this case 4 is a leg and 14 and 17 is the hyptonuese
