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Degger [83]
3 years ago
12

Square root of 32 x square root of 1 over 18

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

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X^2+15x=-45 solve by factoring
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1 Move all terms to one side.

{x}^{2}+15x+45=0

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A planr leaves and flies due north at 280 miles per hour. AT the same time another plane takes off from the same airport and fli
kompoz [17]

Answer:

Distance between the two planes after 1 hour = 410 miles

Step-by-step explanation:

Given - A plane leaves and flies due north at 280 miles per hour. At

            the same time another plane takes off from the same airport

            and flies due east at a speed of 300 miles per hour.

To find - What is the distance between the two planes after 1 hour ?

Proof -

Given that , Plane 1 flies due north at a speed of 280 miles per hour.

So,

Total distance traveled in 1 hour = 280 miles

Also,

Plane 2 flies due east at a speed of 300 miles per hour.

So,

Total distance traveled in 1 hour = 300 miles.

The diagram is as follows :

Now,

We have to find the distance after 1 hour i.e. AC

In Triangle ABC ,

By using Pythagoras theorem, we get

AC² = BC² + AB²

⇒AC² = (300)² + (280)²

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⇒AC² = 168,400

⇒AC = √168,400

⇒AC = 410.366 ≈ 410

∴ we get

Distance between the two planes after 1 hour = 410 miles

7 0
3 years ago
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