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Degger [83]
2 years ago
12

Square root of 32 x square root of 1 over 18

Mathematics
1 answer:
lisov135 [29]2 years ago
7 0
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

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Nadusha1986 [10]

Answer:

17m

Step-by-step explanation:

Add up 4m and 4.5m. 8.5

Multiply that number by 2. 17

6 0
2 years ago
Read 2 more answers
What is the product of (2x-7) and (3x + 3)?
eduard
<h3>✒️EVALUATION </h3>

==================================

\large\sf\underline{Problem:}

What is the product of (2x-7) and (3x + 3)?

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

==================================

\large\sf\underline{Answer:}

\qquad \qquad \huge \rm Letter\:B.

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

\large\sf\underline{Solution:}

Here we have the given choices:

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}

Therefore, the correct option is letter B.

==================================

ヾ(^-^)ノ

3 0
2 years ago
DOES ANYONE KNOW HOW TO DO THIS????????
castortr0y [4]

Answer:

1. figure 4

2. Figure 1

3. Figure 3

Step-by-step explanation:

1. r is the degree of the line or group of dots that makes a line. for r=1, the line is going to be as close to a linear line as possible. the dots will be close together a make either a close or perfect straight line. This is why we pick figure 4, because the points are decently close together and form a positive slope.

2. a linear relationship can be tested by a straight line test, and in this case you pick the figure that fails the test the most. in this case, Figure 1 fits.

3.  looking for r=-1 is looking for the opposite of r=1, so since figure 3 is the opposite of figure 4, we know it fits the description

4 0
3 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.​
Leni [432]

Answer:

To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;

3·4ⁿ is divisible by 3 and 51 is divisible by 3

Where we have;

S_{(n)} =  3·4ⁿ + 51

S_{(n+1)} = 3·4ⁿ⁺¹ + 51

S_{(n+1)} - S_{(n)} = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ

S_{(n+1)} - S_{(n)} = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ

∴ S_{(n+1)} - S_{(n)} is divisible by 9

Given that we have for S₀ =  3×4⁰ + 51 = 63 = 9×7

∴ S₀ is divisible by 9

Since  S_{(n+1)} - S_{(n)} is divisible by 9, we have;

S_{(0+1)} - S_{(0)} =  S_{(1)} - S_{(0)} is divisible by 9

Therefore S_{(1)} is divisible by 9 and S_{(n)}  is divisible by 9 for all positive integers n

Step-by-step explanation:

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