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nignag [31]
3 years ago
8

You earned an 82% on a math test. You answered 18 questions correctly.How many questions were on the test

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

22

Step-by-step explanation:

The easiest way to do this is to multiply the number you got right by 1+ the percent you got wrong. In this case it would be 1+.18. If you multiply 18 by 1.18 you get 21.24. Because you cant have part of a question you need to round up. To check you can divide 18 by 22 and you get 81.81. I hope this helps!

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At a graduation dinner there were 47 guests in all. An equal number of guests were seated at each of 7 large​ tables, and 5 ​lat
Lesechka [4]
5 guests are late, making 42 present to split 7 tables. 42/7=6 x=6
3 0
2 years ago
Which set of three numbers can be used to make a right triangle?
Kipish [7]

Answer:

a2+b2=c2

32+42=52

9+16=52

25=52

square root of 25 is 5

Step-by-step explanation:

so 3,4,5, is the answer

5 0
2 years ago
Read 2 more answers
A card is drawn from the numbered from 5 to 30 find the probability of getting square or even numbered card
skelet666 [1.2K]

Answer:

5/6 maybe I'm not sure but hey it's worth a shot

3 0
2 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
2 years ago
Can someone please help me with this proof?!
Elza [17]

Answer:

because AC and BD bis => AX = XC; BX = XD

ΔAXD ≅ ΔCXB (SAS) because: AX = CX

                                                    DX = BX

                                                    m∠AXD = m∠BXC ( 2 opposing angles)

because ΔAXD ≅ ΔCXB (SAS)

=> AD = BC and m∠DAX = m∠BCX

because m∠DAX = m∠BCX => AD//BC

ABCD has AD = BC and AD//BC => ABCD is a parallelogram

Step-by-step explanation:

4 0
3 years ago
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