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3 years ago

Compare and contrast an ocean trench to a mid-ocean range.

1 answer:

7 0

according to a geography site "ocean trenches and ridges. Trench: very deep, elongated cavity bordering a continent or an island arc; it forms when one tectonic plate slides beneath another. Ridge: underwater mountain range that criss-crosses the oceans and is formed by rising magma in a zone where two plates are moving apart."

Hope this helps

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La importancia del Mediterraneo

Nina [5.8K]

El Mar Mediterráneo es un mar que ha tenido una gran importancia para el desarrollo de la humanidad y de su cultura, siendo un lugar donde se crearon varias de las grandes civilizaciones que marcaron la historia.

8 0

3 years ago

What is the value of X6? Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

3 years ago

24)

liq [111]

The best bibliogaphic entry would probably be: Smythe, Clark. Unsinkable: Folly on the Titanic Little, Brown: New York, 1976.

That is because it seems to be a book about the Titanic itself, whereas the other ones have to do with:

topics which are less directly related to the subject-matter (the first entry is about maritime laws and the third one is about the animal and plant populations of the lands near the North Pole),
personal, relative accounts of the events (like the fourth entry, which is an autobiography of a survivor and therefore describes the wreck through the character's own perspective) as opposed to more factual material.

6 0

3 years ago

When transporting goods, manufacturers are primarily concerned with

melomori [17]

Answer: Most likely B, Cost and time.

If I was transporting goods, I wouldn't want to pay more than I need to.

Hope this helped.

4 0

3 years ago

What’s the best way to remember this all for my test tomorrow in social studies?

Furkat [3]

You just have to go over it over and over until you can memorize it and remember where everything is