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The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.
<h3>What is the mean of a distribution?</h3>The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.
From the parameters given:
Low-temperature Frequency
40 - 44 2
45 - 49 5
50 - 54 9
55 - 59 6
60 - 64 3
The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.
The class midpoint of 40 - 44 is
The class midpoint of 45 - 49 is
The class midpoint of 50 - 54 is
The class midpoint of 55 - 59 is
The class midpoint of 60 - 64 is
Now, the table can be represented as:
Low-temperature Frequency x
40 - 44 2 42
45 - 49 5 47
50 - 54 9 52
55 - 59 6 57
60 - 64 3 62
The mean can now be determined as follows:
Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F
Learn more about the mean of frequency distribution here:
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
NOT PROPORTIONAL
Step-by-step explanation:
The given two fractions are: and
.
Proportional fractions are those which have the same value when to reduced to the simplest form.
Consider two fractions and
.
We say they are proportional if .
Or, if then we can say the fractions are proportional.
Here the fractions are: and
.
LHS: 5 X 10 = 50.
RHS: 8 X 8 = 64.
Clearly they are not equal. So, we can say these two fractions are not proportional.