3y -1 =13 - 4y
7y = 14
y= 2
The equation has one solution
Answer:
x=5
Step-by-step explanation:
5-3=2
Answer:
The answer is
![x = 12 \\ y = 20 \\ z = 15](https://tex.z-dn.net/?f=x%20%3D%2012%20%5C%5C%20y%20%3D%2020%20%5C%5C%20z%20%3D%2015)
Step-by-step explanation:
By using Pythagoras low
Then we can find that
![{y}^{2} = {x}^{2} + {16}^{2} \\ {z}^{2} = {x}^{2} + {9}^{2} \\ {y}^{2} + {z}^{2} = {25}^{2} \\ then \\ {x}^{2} + {9}^{2} + {x}^{2} + {16}^{2} = {25}^{2} \\ 2 {x}^{2} = 288 \\ x = 12 \\ By \: substituting \: x \: into \: the \: previous \: equations \\ then \: \\ y = 20 \\ z = 15](https://tex.z-dn.net/?f=%20%7By%7D%5E%7B2%7D%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%7B16%7D%5E%7B2%7D%20%20%5C%5C%20%20%7Bz%7D%5E%7B2%7D%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20%5C%5C%20%20%7By%7D%5E%7B2%7D%20%20%20%2B%20%20%7Bz%7D%5E%7B2%7D%20%20%3D%20%20%7B25%7D%5E%7B2%7D%20%5C%5C%20%20then%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%7B9%7D%5E%7B2%7D%20%20%2B%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%7B16%7D%5E%7B2%7D%20%20%3D%20%20%7B25%7D%5E%7B2%7D%20%20%5C%5C%202%20%7Bx%7D%5E%7B2%7D%20%20%3D%20288%20%5C%5C%20x%20%3D%2012%20%5C%5C%20By%20%20%5C%3A%20substituting%20%5C%3A%20%20x%20%5C%3A%20%20into%20%20%5C%3A%20the%20%20%5C%3A%20previous%20%5C%3A%20%20equations%20%5C%5C%20then%20%5C%3A%20%20%5C%5C%20y%20%3D%2020%20%5C%5C%20z%20%3D%2015)
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Answer:
power of quotient
Step-by-step explanation:
We have been given an expression and we are asked to choose the correct rule to simplify our given expression.
Since our given expression is a fraction raised to 3rd power. Power of a quotient rule states when a quotient is raised to an exponent, then the exponent is distributed to both numerator and denominator of the quotient.
Using power of a quotient rule, we will get, (\frac{p}{q} )^3=\frac{p^3}{q^3}