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RUDIKE [14]
3 years ago
8

The cherries and grapes are in bags of 10. Ben gives Emma some of the bags. What math questions could Ben ask about the bags of

fruit?
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

travis scott said straight up then thats the answer

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-2|5x+3|>=4 i dont have the bigger equal simbols , please help me with this question ;((
ipn [44]

Step-by-step explanation:

-2|5x + 3| >= 4

|5x + 3| <= -2

Since absolute value is never negative, there are no real values for x.

6 0
2 years ago
Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
Solve each equation. <br> 2y=7(y−2)+4<br> y = <br> 4x=6−2(2−x) <br> x =
aliya0001 [1]

Answer:

y=2 and x=1

Step-by-step explanation:

2y=7y-14+4

2y-7y=-14+4

-5y=-10/-5

y=2

4x=6-4+2x

4x-2x=6-4

2x=2/2

x=1

5 0
2 years ago
Can someone help please?
Zina [86]
The correct answer is b!
6 0
3 years ago
Read 2 more answers
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