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Angelina_Jolie [31]
3 years ago
14

Which rationale best describes why the functions are inverses? The functions intersect each other The functions have the same ge

neral curve. The functions are reflections over the line y = x One function has an x- intercept and the other has a y-intercept
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0

Answer: it’s C on edge2020 (the functions are reflections over the line y= x

Step-by-step explanation:

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5 quarts of oil for her car. How many fluid ounces is that
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1 quart = 31.9995 fluid ounces

5 quarts = 159.997 fluid ounces.
4 0
3 years ago
Find the value of f(9) and g(-9) if f(×) = -7×-9 and g(×) = 6×3-23×
Vlada [557]

Answer:

f(9)= -72

g(-9)= 225

Step-by-step explanation:

First put the original equation

f(x)=-7x-9

Next plug in the number f(9)

f(9)=-7(9)-9

After multiply -7(9) which gets you -63

f(9)=-63-9

Then subtract -63-9 which gets you -72

f(9)=-72

-----------------------------------------------------------

First put the original

g(x)=6x3-23x

Next plug in the number g(-9)

g(-9)=6x3-23(-9)

After multiply 6x3 which gives you 18 then multiply -23(-9)

g(-9)=18+207

then add 18+207 which gives you 225

g(-9)=225

8 0
3 years ago
More than one unknown in a word problem can be represented in terms of the same variable assigned to first unknown. true of fals
Sergeeva-Olga [200]
This is clearly false as it will just mess up the question.
6 0
3 years ago
Read 2 more answers
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
2 years ago
Plzzzzzzz give me notes of dna replication​
miskamm [114]
- A DNA strand can act as a template for synthesis of a new nucleic acid strand in which each base forms a hydrogen-bonded pair with one on the template strand (G with C, A with T, or A with U for RNA molecules). The new sequence is thus complementary to the template strand. The copying of DNA molecules to produce more DNA is known as DNA Replication.

-DNA replication takes place at a Y-shaped structure called a replication fork. A self-correcting DNA polymerase enzyme catalyzes nucleotide polymerization in a 5ʹ-to-3ʹ direction, copying a DNA template strand with remarkable fidelity. Since the two strands of a DNA double helix are antiparallel, this 5ʹ-to-3ʹ DNA synthesis can take place continuously on only one of the strands at a replication fork (the leading strand).

-On the lagging strand, short DNA fragments must be made by a “backstitching” process. Because the self-correcting DNA polymerase cannot start a new chain, these lagging-strand DNA fragments are primed by short RNA primer molecules that are subsequently erased and replaced with DNA.

-DNA replication requires the cooperation of many proteins. These include:

*DNA polymerase and DNA primase to catalyze nucleoside triphosphate polymerization;
*DNA helicases and single-strand DNA-binding (SSB) proteins to help in opening up the DNA helix so that it can be copied;
*DNA ligase and an enzyme that degrades *RNA primers to seal together the discontinuously synthesized laggingstrand DNA fragments;
*DNA topoisomerases to help to relieve helical winding and DNA tangling problems. *Many of these proteins associate with each
other at a replication fork to form a highly efficient “replication machine,” through which the activities and spatial movements of the individual components are coordinated.

Major steps involved in DNA replication are as follows:

*Each strand in a parental duplex DNA acts as a template for synthesis of a daughter strand and remains basepaired to the new strand, forming a daughter duplex (semiconservative mechanism).
*New strands are formed in the 5′ to 3′ direction.
*Replication begins at a sequence called an origin.
*Each eukaryotic chromosomal DNA molecule contains multiple replication origins.
*DNA polymerases, unlike RNA polymerases, cannot unwind the strands of duplex DNA and cannot initiate synthesis of new strands complementary to the template strands.
*Helicases use energy from ATP hydrolysis to separate the parental (template) DNA strands.
*Primase synthesizes a short RNA primer, which remains base-paired to the template DNA.
*This initially is extended at the 3′ end by DNA polymerase α (Pol α), resulting in a short (5′ )RNA- (3′)DNA daughter strand.
*Most of the DNA in eukaryotic cells is synthesized by Pol ẟ, which takes over from Pol α and continues elongation of the daughter strand in the 5′ to 3’direction.
*Pol ẟ remains stably associated with the template by binding to Rfc protein, which in turn binds to PCNA, a trimeric protein that
encircles the daughter duplex DNA.
*DNA replication generally occurs by a bidirectional mechanism in which two replication forks form at an origin and move in opposite directions, with both template strands being copied at each fork.
*Synthesis of eukaryotic DNA in vivo is regulated by controlling the activity of the MCM helicases that initiate DNA replication at multiple origins spaced along chromosomal DNA.
*At a replication fork, one daughter strand (the leading strand) is elongated continuously.
*The other daughter strand (the lagging strand) is formed as a series of discontinuous Okazaki fragments from primers synthesized every few hundred nucleotides.
*The ribonucleotides at the 5′ end of each Okazaki fragment are removed and replaced by elongation of the 3′ end of the next Okazaki fragment.
*Finally, adjacent Okazaki fragments are joined by DNA ligase.
4 0
3 years ago
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