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Misha Larkins [42]
4 years ago
5

Is molecular weight different from molecular mass?​

Chemistry
1 answer:
Korolek [52]4 years ago
6 0

Answer:

Molecular weight is how much each molecule weights, while molecular mass is how many molecules there are in a certain element

You might be interested in
Convert 850 mm Hg to kPa. *
Feliz [49]

Answer:

113.324 KPA

Explanation:

4 0
3 years ago
State the number of protons, electrons and neutron ​
skad [1K]

Answer:

You didn't show which element it is. The proton is the atomic number, the electron is the same number of protons, and the neutron is the atomic mass rounded to the nearest whole number minus the proton.

Explanation:

4 0
3 years ago
pure substance x is a green powder. when heated, it gives off a gas and changes to a black powder. is substance x an element or
gogolik [260]

I'd say it is an element. It is not a compound, it doesn't do things on its own like us. It's an element like fire and water.

7 0
3 years ago
Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq
zhannawk [14.2K]

Answer: H^++CN^-\rightarrow HCN, product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN

The net ionic equation will not contain spectator ions which are K^+ and Cl^-:

H^++CN^-\rightarrow HCN

The reaction is product favoured.

 

5 0
3 years ago
If 57.0 g of b2o3 is added to 44.7 g of cl2 and 68.8 g of c, what is the theoretical yield of boron trichloride?
sdas [7]
(57.0 g B2O3 / (69.6202 g B2O3/mol) x (4mol BCI3 / 2 mol B2O3) = 1.64 mol BC13

(44.7 g C12) / (70.9064 g C12/mol) x (4mol BCI3 / 6mol C12) = 0.42027 mol BC13

(68.8 g C) / (12.01078 G C/mol) x (4mol BCI3 / 3 mol C) = 7.63 mol BCI3

C12 is the limiting reactant.

(0.42027 mol BCI3) X (117 . 170 g BCI3/mol) = 49.2 g BCI3 in theory.
6 0
4 years ago
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