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lianna [129]
2 years ago
6

Sketch the region R defined by 1≤ x≤ 2 and 0≤ y≤ 1/x^3

Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0
On the attachment, there is the graph for the region "R" and the calculations for the value a and b. 

the theory is that you have to choose a value that is between the range and assume that this value will divide the area into two equal parts. This is done for x = a

For
"y" you have to change the integral from dx to dy and you have to divide the region into 2 parts, given that the area cannot be calculated by 1 integral equation, so you proceed to calculate the rectangular area and take this area into consideration, for the same procedure as before. 

Then you calculate again the value y = b and that's it.

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Answer:

Inverse function is f^{-1}(x)=\frac{3}{2}x+\frac{51}{2}.

Step-by-step explanation:

Given function is f\left(x\right)=\frac{2}{3}x-17.

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Step 1: replace f(x) with y

y=\frac{2}{3}x-17

Step 2: switch x and y

x=\frac{2}{3}y-17

Step 3: solve for y

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Hence required inverse function is f^{-1}(x)=\frac{3}{2}x+\frac{51}{2}.

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3 years ago
Witch of the s-values satisfy the following inequality?
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7 0
2 years ago
Please help me on this one.
EleoNora [17]
3(j+4)-9=9
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An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of
Keith_Richards [23]
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
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tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
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Therefore, the height of the building is 75.4 feet.
8 0
2 years ago
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