Ask question

Ask question

All categories

2 years ago

7

a neophyte is a beginner. on the first day of classes, 28,000 students arrived at the university campus. if three-sevenths were

neophytes, how many were not neophytes?

2 answers:

navik [9.2K]2 years ago

7 0

Answer:

16 ,000 students are not neophytes.

lara [203]2 years ago

7 0

There is 16 that were not neophytes.

You might be interested in

A rancher is ordering a box of cube-shaped salt licks. the edge length of each salt lick are 5/12 foot. is the volume of one sal

strojnjashka [21]

Answer:

0.0723 cubic feet < 1 cubic foot.

Step-by-step explanation:

A cube-shaped salt lick is ordered by a rancher and the length of each salt lick is $\frac{5}{12}$ foot.

Therefore, the side length of each salt lick of cube-shape is $\frac{5}{12}$ foot.

So, the volume of each salt lick is $(\frac{5}{12} \times \frac{5}{12} \times \frac{5}{12}) = \frac{125}{1728} = 0.0723$ cubic feet.

Hence, this volume is less than 1 cubic foot. (Answer)

5 0

3 years ago

Humihingi po ako sa inyo ng tulong po, sana matulungan nyo po ako dito☝

suter [353]

I Domitila get hungry :

Step-by-step explanation:

3 0

2 years ago

HELP PLEASE HURRY!!

frozen [14]

Answer:

9.9225 E 34.

E = exponent

= 9.9225 x 10^34

Step-by-step explanation:

5 0

3 years ago

The population of bacteria can be modeled by the function below, where t represents the time since the population started decayi

Oksana_A [137]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete. I will assume the function is:

$f(t) = 15(0.86)^t$

Required

Determine the rate of decay

In an exponential function $f(x) = ab^x$ ,

The decay rate of the function is calculated as:

$1 - r = b$

By comparison:

$b = 0.86$

So, the equation becomes:

$1 - r = 0.86$

Make r the subject

$r = 1 - 0.86$

$r = 0.14$

<em>The rate of decay is 0.14</em>

3 0

3 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago