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ddd [48]
3 years ago
7

a neophyte is a beginner. on the first day of classes, 28,000 students arrived at the university campus. if three-sevenths were

neophytes, how many were not neophytes?​
Mathematics
2 answers:
navik [9.2K]3 years ago
7 0

Answer:

16 ,000  students are not neophytes.

lara [203]3 years ago
7 0

There is 16 that were not neophytes.

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Double-Angle and Half-Angle Identiies [See Attachment] Question 5
sergey [27]

Thought I did this one but it was just very similar. Again there's a q and a theta I'm just going to assume are the same.



\sin \theta = \pm \sqrt{1 - \cos^2 \theta}


\sin \theta = + \sqrt{1 - (3/5)^2} = \frac 4 5


I picked positive because we're in the first quadrant.


\sin 2 \theta = 2 \sin \theta \cos \theta


\sin 2 \theta = 2 (\frac 4 5)(\frac 3 5) = \frac {24}{25}



5 0
3 years ago
Please help!! i’ll give brainliest
lana66690 [7]

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6 0
2 years ago
An evergreen nursery usually sells a certain shrub after 5 years of growth and shaping. The growth rate during those 5 years is
ivanzaharov [21]

Answer:

h(t) = 0.75t^2 + 4t + 12

Step-by-step explanation:

The equation given calculates the derivative of the height in relation to the time, that is, the rate of change of the height. To find the equation for the height, we need to integrate this equation:

dh/dt = 1.5t + 4

Multiplying both sides by 'dt', we have:

dh = (1.5t + 4)dt

Using the integral in both sides:

\int dh = \int (1.5t + 4) dt

h = 0.75t^2 + 4t + h(0)

h = 0.75t^2 + 4t + 12

So the height after t years is represented by this equation:

h(t) = 0.75t^2 + 4t + 12

3 0
3 years ago
5=a/2(b+c) <br><br> Solve for b
yaroslaw [1]

Answer:

b = \dfrac{a - 10c}{10}

Step-by-step explanation:

\begin{array}{rcl}5 & = & \dfrac{a}{2(b + c)}\\\\5& = & \dfrac{a}{2b + 2c}\\\\10b + 10c & = & a\\10b & = & a - 10 c\\b & = & \mathbf{\dfrac{a - 10c}{10}}\\\end{array}

8 0
2 years ago
Which statement is true?
Wittaler [7]

Answer:

The y-intercept of Function A is less than the y-intercept of Function B.

Step-by-step explanation:

Function A's y-intercept would be (0, -1) and Function B's y-intercept is (0, 4). Therefore, Function A's y-intercept is less than Function B's.

5 0
2 years ago
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