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lions [1.4K]
3 years ago
15

Find the slope that passes through these two points.

Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

m =  \frac{ - 1 - 4}{2  + 3}  \\ m =  - 1

Good luck!

Intelligent Muslim,

From Uzbekistan.

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Whats (4.2×10^6)+(2.25 × 10^5) in scientific form
lys-0071 [83]
We are going to rewrite both numbers:
 (4.2 × 10 ^ 6) = 4200000
 (2.25 × 10 ^ 5) = 225000
 Adding we have:
 4200000 + 225000 = 4425000
 Rewriting in exponential notation we have:
 4425000 = 4,425 * 10 ^ 6
 Answer:
 
(4.2 × 10 ^ 6) + (2.25 × 10 ^ 5) is equal to:
 
4,425 * 10 ^ 6
8 0
3 years ago
How do you prove each of the following theorems using either a two-column, paragraph, or flow chart proof?
lilavasa [31]

All the theorems are proved as follows.

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices and three angles.

1. The Triangle sum Theorem

According to the Triangle Sum Theorem, the sum of a triangle's angles equals 180 degrees.

To create a triangle ABC, starting at point A, move 180 degrees away from A to arrive at point B.

We turn 180 degrees from B to C and 180 degrees from C to return to A, giving a total turn of 360 degrees to arrive to A.

180° - ∠A + 180° - ∠B + 180° - ∠C = 360°

- ∠A - ∠B  - ∠C = 360° - (180°+ 180°+ 180°) = -180°

∠A + ∠B  + ∠C = 180°

(Hence Proved)

2. Isosceles Triangle Theorem

Considering an isosceles triangle ΔABC

with AB = AC, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as AB = AC

sin B = sin C

angle B = angle C

3.Converse of the Isosceles theorem

Consider an isosceles triangle ΔABC with ∠B= ∠C, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as  ∠B= ∠C ,

AB = AC

4. Midsegment of a triangle theorem

It states that the midsegment of two sides of a triangle is equal to (1/2)of the third side parallel to it.

Given triangle ABC with midsegment at D and F of AB and AC respectively, DF is parallel to BC

In ΔABC and ΔADF

∠A ≅ ∠A

BA = 2 × DA, BC = 2 × FA

Hence;

ΔABC ~ ΔADF (SAS similarity)

BA/DA = BC/FA = DF/AC = 2

Hence AC = 2×DF

5.Concurrency of Medians Theorem

A median of a triangle is a segment whose end points are on vertex of the triangle and the middle point of the side ,the medians of a triangle are concurrent and  the point of intersection is inside the triangle known as Centroid .

Consider a triangle ABC , X,Y and Z are the midpoints of the sides

Since the medians bisect the segment AB into AZ + ZB

BC into BX + XB

AC into AY + YC

Where:

AZ = ZB

BX = XB

AY = YC

AZ/ZB = BX/XB = AY/YC = 1

AZ/ZB × BX/XB × AY/YC = 1 and

the median segments AX, BY, and CZ are concurrent (meet at point within the triangle).

To know more about Triangle

brainly.com/question/2773823

#SPJ1

8 0
1 year ago
Find the common ratio of the geometric sequence –5,–30, -180,...
Murljashka [212]

Answer:

6

Step-by-step explanation:

You have to find what to multiply by to get to the next term

-30 ÷ -5 = 6

- 180 ÷ -30 = 6

therfore the common ratio is 6

5 0
2 years ago
Read 2 more answers
Find the next two terms in this<br> sequence.<br> 1, -3, 9, -27, 81, [ ? ], [ ? ]
Katyanochek1 [597]

Answer:

the answers are -243 and 729

Step-by-step explanation:

you multiply each by -3. 1x-3 gives you -3. -3x-3 gives you 9. -3x9 gives you -27. -27x-3 gives you 81. 81x-3 gives you -243 and -243x-3 gives you 729. i hope this helps.

3 0
1 year ago
Pls help on this question ​
sveticcg [70]

Answer:

178.571429

Step-by-step explanation:

Area of square - 10*10 m = 100m

Area of the semicircle = Diameter = 10m, so the radius = 5m

Area of circle = \pi r^{2}

=> Area = 22/7 * 25

=> 78.5714286

Area of figure = 78.5714286 + 100 = 178.571429

Hope it helps :)

6 0
3 years ago
Read 2 more answers
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