To get the equation of the line, you need two points that belong to this line.
From the given graph, we can choose any two points: (0,-4) and (-2,0)
The general for of the linear straight line is:
y = mx + c where m is the slope and c is the y-intercept
First, we will calculate the slope using the following rule:
slope = (y2-y1) / (x2-x1)
slope (m) = (0--4) / (-2-0) = 4/-2 = -2
The equation of the line now is: y = -2x + c
Then, we will get the value of the c. To do so, we will choose any point and substitute in the equation. I will choose the point (0,-4)
y = -2x + c
-4 = -2(0) + c
c = -4
Based on the above calculations, the equation of the line is:
y = -2x - 4
Answer:
Step-by-step explanation
Note that
Interest is represented by I=1326
The principal is represented by P=47,600
Rate is R =4%
And Time is year
Interest is calculated using the formulae,
I =PRT/100
From the above formulae, time can be calculated as
T=100I/PR
T= 100×1326/(47600×4)
T= 132600/190400
T= 0.6964 years
To convert to days, multiply by 365(since those no of days make a year)
T= 0.6964×365=254 days
This was approximated to the nearest day
Answer is 254 days
Answer:
x=-12
Step-by-step explanation:
(-22 + 3x) /( 3x+7) =2
Multiply each side of the equation by 3x+7
-22+3x = 2(3x+7)
Then distribute
-22 +3x = 6x+14
Subtract 3x from each side
-22 = 3x+14
Subtract 14 from each side
-36 = 3x
Divide by 3
-12 =x
Answer:
I don't have the graph, but I'll explain what you need to do. Plot a point with the coordinates (1,3.5), (2,7), (3,10.5), and (4,14). Now draw a straight line connecting al these pints but don't go past the origin into the negative as in this situation it is not possible. There! Now you have a graph :)
Answer:
≈23.6 kg left.
Step-by-step explanation:
For determining this, we can simply use an exponential decay equation representing this scenario:
a: the initial amount
t: the amount of time
h: the half life
Now, substitute the numbers into the equation:

Now, solve this equation:

Use a calculator to solve for y:
y= 200(0.118)
y≈23.6 kg left.