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vazorg [7]
3 years ago
10

Cassie received a 25%-off coupon and a $10.00-off coupon from a department store. She visits the department store during a tax-f

ree sale and plans to spend no more than $26.75. She also plans to use both of the coupons she received on her purchase. If this situation is modeled by the inequality below, what must be the original purchase total, x, before the discounts are applied? 0.75x - $10.00 < $26.75
A.
x < $22.33
B.
x < $49.00
C.
x < $25.67
D.
x < $36.75
Mathematics
1 answer:
hjlf3 years ago
4 0
The answer is B.) x<$49.00
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Find a1, for the arithmetic series<br> with S14 = - 420 and d = -6.
faust18 [17]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} n = 14\\ d= -6 \end{cases} \\\\\\ a_{14}=a_1+(14-1)(-6)\implies a_{14}=a_1+(13)(-6)\implies a_{14}=a_1-78 \\\\[-0.35em] ~\dotfill

\bf \textit{sum of a finite arithmetic sequence} \\\\ S_n=\cfrac{n(a_1+a_n)}{2}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{last term's}\\ \qquad position\\ a_1=\textit{first term}\\ \cline{1-1} n= 14\\ S_{14}=-420\\ a_{14}=a_1-78 \end{cases}\implies S_{14}=\cfrac{n(a_1+a_{14})}{2} \\\\\\ -420=\cfrac{14[a_1+(a_1-78)]}{2}\implies -420=7(2a_1-78)\implies \cfrac{-420}{7}=2a_1-78 \\\\\\ -60=2a_1-78\implies 18=2a_1\implies \cfrac{18}{2}=a_1\implies 9=a_1

8 0
3 years ago
Pls pls pls pls help. im so stressed rn
Sloan [31]

Answer:

The function role is +2 for x, and -1 for y.

Step-by-step explanation:

The reason for my answer is because as you can see on the table;

For X, it starts at 0 and counts up by 2. For Y, it starts at 2 and counts back by 1.

6 0
2 years ago
Two trains leave the same station at the same time, but are headed in opposite directions. One train travels at 70 mph and the o
uranmaximum [27]

Let

x--------> the time in hours

y-------> the distance in miles

we know that

The speed is equal to

Speed=\frac{distance}{time}

in this problem

Speed=\frac{y}{x}

y=(Speed)*x

<u>Equation First Train</u>

y1=70x

<u>Equation Second Train</u>

y2=80x

y1+y2=600\ miles ---------> equation 1

Substitute the values of y1 and y2 in the equation 1

70x+80x=600

Solve for x

150x=600

x=4\ hours

therefore

<u>the answer is</u>

4\ hours

4 0
3 years ago
Read 2 more answers
What equals 60 36 and 48
Deffense [45]
60. 1 times 60 equals 60 2 times 30 equals 60 3 times 20 equals 60 4 times 15 equals 60 5 times 12 equals 60 6 times 10 equals 60 10 times 6 equals 60 12 times 5 equals 60 15 times 4 equals 60 20 times 3 equals 60 30 times 2 equals 60 60 times 1 equals 60                                                                                                                                                                                                     1 times 36 equals 36 2 times 18 equals 36 3 times 12 equals 36 4 times 9 equals 36 6 times 6 equals 36 9 times 4 equals 36 12 times 3 equals 36 18 times 2 equals 36 36 times 1 equals 36

1 times 48 equals 48 2 times 24 equals 48 3 times 16 equals 48 4 times 12 equals 48 6 times 8 equals 48 8 times 6 equals 48 12 times 4 equals 48 16 times 3 equals 48 24 times 2 equals 48 48 times 1 equals 48
7 0
3 years ago
Read 2 more answers
1-2m-5m=15 multistep homework
Montano1993 [528]

1-2m-5m=15

combine like terms

1 -7m = 15

subtract 1 from each side

1-1-7m = 15-1

simplify

-7m = 14

divide by -7

-7m/-7 = 14/-7

simplify

m = -2


6 0
3 years ago
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