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3 years ago

7

the cross of a water bin is shaped like a trapezoid. the base of the trapezoid are 22 feet and 4 feet long. it has a area of 26

square feet. what is the height of the cross section?

1 answer:

Rzqust [24]3 years ago

4 0

Just sayin' you shouldn't use up all ur points on one question

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julie has 10 yards of ribbon she divides the ribbon into 3 equal pieces and uses 2 of the pieces on gifts how much ribbon does s

Lunna [17]

Answer:

2/3

Step-by-step explanation:

if we divide 10 by 3 then we get 3.3 repeating so just use the fraction 1/3. if you use 2 of the divided lengths then you get 2/3

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3 years ago

How can bees dying affect all four spheres of the Earth? (lithosphere, biosphere, atmosphere, and hydrosphere)

labwork [276]

Answer:

Step-by-step explanation:

For example, the atmosphere mixes down into the other spheres and releases precipitates; the hydrosphere overlaps onto land surfaces and water vapor rises up into the atmosphere; the biosphere reaches up into the atmosphere, down into soils and rock, and throughout the oceans, exchanging gases, water and nutrients

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3 years ago

17u-8u=18<br> Can u explain how this works

Brilliant_brown [7]

U is 2
You collect like terms meaning you do 17-8= 9u
9u=18 divide both sides by 9 and get U=9

8 0

3 years ago

What is 7x+6x because in math we are doing properties of operations and I need help with it and I don't know how to do it

Sloan [31]

Answer:

13x

Step-by-step explanation:

7x+6x=13x. But since i do not have a second part of the question i can not tell you what x equals

4 0

3 years ago

Read 2 more answers

Write the equation of the quadratic function whose graph passes through <img src="https://tex.z-dn.net/?f=%28-3%2C2%29" id="TexF

blagie [28]

Answer:

$f(x)=x^2+3x+2$

Step-by-step explanation:

We want to write the equation of a quadratic whose graph passes through (-3, 2), (-1, 0), and (1, 6).

Remember that the standard quadratic function is given by:

$f(x)=ax^2+bx+c$

Since it passes through the point (-3, 2). This means that when $x=-3$ , $f(x)=f(-3)=2$ . Hence:

$f(-3)=2=a(-3)^2+b(-3)+c$

Simplify:

$2=9a-3b+c$

Perform the same computations for the coordinates (-1, 0) and (1, 6). Therefore:

$0=a(-1)^2+b(-1)+c \\ \\0=a-b+c$

And for (1, 6):

$6=a(1)^2+b(1)+c\\\\ 6=a+b+c$

So, we have a triple system of equations:

$\left\{ \begin{array}{ll} 2=9a-3b+c &\\ 0=a-b+c \\6=a+b+c \end{array} \right.$

We can solve this using elimination.

Notice that the b term in Equation 2 and 3 are opposites. Hence, let's add them together. This yields:

$(0+6)=(a+a)+(-b+b)+(c+c)$

Compute:

$6=2a+2c$

Let's divide both sides by 2:

$3=a+c$

Now, let's eliminate b again but we will use Equation 1 and 2.

Notice that if we multiply Equation 2 by -3, then the b terms will be opposites. So:

$-3(0)=-3(a-b+c)$

Multiply:

$0=-3a+3b-3c$

Add this to Equation 1:

$(0+2)=(9a-3a)+(-3b+3b)+(c-3c)$

Compute:

$2=6a-2c$

Again, we can divide both sides by 2:

$1=3a-c$

So, we know have two equations with only two variables:

$3=a+c\text{ and } 1=3a-c$

We can solve for a using elimination since the c term are opposites of each other. Add the two equations together:

$(3+1)=(a+3a)+(c-c)$

Compute:

$4=4a$

Solve for a:

$a=1$

So, the value of a is 1.

Using either of the two equations, we can now find c. Let's use the first one. Hence:

$3=a+c$

Substitute 1 for a and solve for c:

$\begin{aligned} c+(1)&=3 \\c&=2 \end{aligned}$

So, the value of c is 2.

Finally, using any of the three original equations, solve for b:

We can use Equation 3. Hence:

$6=a+b+c$

Substitute in known values and solve for b:

$6=(1)+b+(2)\\\\6=3+b\\\\b=3$

Therefore, a=1, b=3, and c=2.

Hence, our quadratic function is:

$f(x)=x^2+3x+2$

5 0

3 years ago